What can be calculated simply should be calculated simply What can be easily calculated should be simply calculated [not only the answer, but also the process] 4 / 5x2 / 7 + 4 / 7 = [detailed formula] 25 and 3 / 8x8 = [detailed formula] 5 / 8 △ 7 / 9 + 3 / 8x9 / 7 = [detailed formula] 99x6 / 25 = [detailed formula] 9 / 10x101 = [detailed formula] 8 / 12 △ 9 + 1 / 9x10 / 13 = [detailed formula] to find the answer! In 10 minutes = = =! Urgent

4 / 5x2 / 7 + 4 / 7 = 4 / 7X2 / 5 + 4 / 7x1 = 4 / 7X (2 / 5 + 1) = 4 / 7x7 / 5 = 4 / 525 and 3 / 8x8 = 25x8 + 3 / 8x8 = 200 + 3 = 2035 / 8 △ 7 / 9 + 3 / 8x9 / 7 = 5 / 8x9 / 7 + 3 / 8x9 / 7 = (5 / 8 + 3 / 8) x9 / 7 = 1x9 / 7 = 9 / 799x6 / 25 = (100-1) X6 / 25 = 100x6 / 25-1x6 / 25 = 4x6-6 / 25 = 24-6 / 25 = 23 and 9 / 259 / 1

Factorization a ^ 2-2a (m-n) + m ^ 2-2mn-3n ^ 2

=a²-2a(m-n)+(m-3n)(m+n)
=(a-m+3n)(a-m-n)

Factorization of m-4mn + 3N by collocation method

The original formula = m ^ 2-4mn + n ^ 2-N ^ 2 + 3N ^ 2 = m ^ 2-4mn + 4N ^ 2-N ^ 2 = (m-2n) ^ 2-N ^ 2 = (m-2n-n) (m-n + n) = m (m-3n) please click the bottom right corner to accept. If you are not satisfied, please ask. Your support is my driving force

If a ^ m = 2, a ^ = 3, then a ^ (m-n) =_____ a^(3n-2n)=_
If a ^ m = 2, a ^ = 3, then a ^ (m-n) =_ a^(3n-2n)=__

1、2/3
2、8/9

2 (square of m-3n-4) - 3 (square of m-4n + 1 / 3)

2 (square of m-3n-4) - 3 (square of m-4n + 1 / 3)
=2m square - 6n-8-3m square + 12n-1
=2m square - 3M square + 12n-6n-8-1
=-Square of M + 6n-9

Factorization x ^ 2-18x-63

x^2-18x-63
=(x-21)(x+3)

First, decompose the algebraic factor, and then evaluate it: 2x (A-2) - Y (2-A), where a = 0.5, x = 1.5, y = - 2

The original formula = 2x (A-2) + y (A-2) = (A-2) (2x + y), when a = 0.5, x = 1.5, y = - 2, the original formula = (0.5-2) × (3-2) = - 1.5

Factorization: 2x ^ 4-32

2x^4-32
=2(x^4-16)
=2(x^2+4)(x^2-4)
=2(x^2+4)(x+2)(x-2)

2X & # 178; - 18 factorization is very urgent!
A picture is the best!

2x²－18=2(x²－9)=2(x+3)(x-3)
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Factorization 18-2x quartic power

Original formula = 2 (3 + x ^ 2) (radical 3 + x) (radical 3-x)