Simple operation of 155 * (23 / 156) + (11 / 156) * 3

Simple operation of 155 * (23 / 156) + (11 / 156) * 3

=(156-1)(23/156)+33/156
=23-23/156+33/156
=23+10/156
=23+5/78
That's 23 times, 5 / 78

How much is 72 times three?

216,

According to the law of 3 ^ 2 times 2 ^ 2 = (2 times 3) ^ 2, 4 ^ 3 times 5 ^ 3 = (4 times 5) ^ 3, (- 8) ^ 1000 times (- 0.125) ^ 1001 =?

(- 8) ^ 1000 times (- 0.125) ^ 1001 = (- 8) ^ 1000 times (- 0.125) ^ 1000 times -0.125 = (- 8 times -0.125) ^ 1000 times -0.125 = -0.125

If x

|3x-2√x²|
=|3x-2(-x)|
=|5x|
Because x

It is known that the sum of the square of the polynomial ax minus ABX plus B and the square of BX plus ABX plus 2a is a monomial, so we can find the relation of ab

A = - B, because the sum is monomial, so the quadratic and primary terms are all reduced, so a = - B

It is known that the sum of the polynomials ax ABX + B and BX + ABX + 2A about X is a monomial. Why?

Solution: ax ABX + B + BX + ABX + 2A = (a + b) x + B + 2a, so: a + B = 0, that is: a = - B; or B + 2A = 0, that is: B = - 2A
Adopt

If the square of the polynomial ax about X - ABX + B and the square of BX + ABX + 2a are a monomial after merging the same class terms, then the relationship between a and B is

(AX & # 178; - ABX + b) + (BX & # 178; + ABX + a) = ax & # 178; - ABX + B + BX & # 178; + ABX + a = (AX & # 178; + BX & # 178;) + (- ABX + ABX) + (B + a) = (a + b) x & # 178; + (a + b) the sum of two polynomials is a binomial, and has two terms. Only when (a + b) = 0, the sum can be a binomial, so: a + B = 0, a, B are

If the sum of the square of the polynomial ax - abx-b and the square of BX + ABX + B is a monomial, then the relationship between a and B is as follows:
A a=b
B A is greater than B
C A is less than B
D uncertainty

According to the known formula, we can get AX2 ABX + B + bx2 + ABX + B = (a + b) x2 + 2B. According to the known formula, we can get a + B = 0
∵ AX2 ABX + B + bx2 + ABX + B = (a + b) x2 + 2B, the sum of polynomial AX2 ABX + B and bx2 + ABX + B is a monomial, B ≠ 0,
∴a+b=0,
a=-b,

If the sum of the square of the polynomial ax - ABX + B and the square of BX + ABX + A is a monomial, then the relation between a and B is

(ax²-abx+b)+(bx²+abx+a)
=ax²-abx+b+bx²+abx+a
=(ax²+bx²)+(-abx+abx)+(b+a)
=(a+b)x²+(a+b)
The sum of two polynomials is a monomial, and has two terms. Only when (a + b) = 0, can the sum be a monomial
So there are: a + B = 0, a, B are opposite numbers

The polynomial (a + B-C) (a-b + C) - (B + C-A) (C-A-B) factorization. Second back!

(a+b-c)(a-b+c)-(b+c-a)(c-a-b)
=(a+b-c)(a-b+c)+(b+c-a)(a+b-c)
=(a+b-c)(a-b+c+b+c-a)
=2c(a+b-c)