2 / (x + 1) + 3 / (x-1) = 11 / X & # 178; - 1

2 / (x + 1) + 3 / (x-1) = 11 / X & # 178; - 1

2/(x+1)+3/(x-1)=11/(x²-1)
2(x-1)+3(x+1)=11
2x-2+3x+3=11
2x+3x=11+2-3
5x=10
x=2
It is the root of the original equation

23 / 6x-2 = 5 / 6x, solve the equation and recover in 5 minutes

23 / 6x-2 = 5 / 6x multiplied by 6 at the same time
23x-12=5x
23x-5x=12
18x=12
x=2/3

6x-x = 2.5

6x-x = 2.5, 5x = 2.5, x = 2.5 / 5x = 0.5, please click "adopt the answer". Your adoption is the driving force for me to answer questions. My friend, please adopt the correct answer in time,

Solve the equation. First, 6x-14 × 3 = 0.2, 5.6x-1.8 = 3.8

6x-14*3=0
6x=42
x=7
5.6x-1.8=3.8
5.6x=3.8+1.8=5.6
x=1

(Y & # 178; + 4) &# 178; - 16y & # 178; factorization

(y²+4)²-16y²=(y²+4)²-(4y)²=(y²+4+4y)(y²+4-4y)=(y+2)²(y-2)²

Factorization: 16x-178; y-64x-178; - 185; - y-178;

Original = - (64x & # 8308; - 16x & # 178; y + Y & # 178;)
=-(8x²-y)²

Given 4x square plus KX minus 5 = (x + 1) times a, (a is a polynomial), then what is a =

If the coefficient of x ^ 2 is 4, then a = (4x + n), and the constant is - 5, then n = - 5,
Then a = 4x-5

Given that 2 is the solution of the equation KX squared minus 4x = 1, what is k = then

Substituting x = 2 into the square of KX - 4x = 1
The square of K * 2-4 * 2 = 1
4k-8=1
k=9/4

Let the square minus (2k minus 1) x + k of the equation KX about X have two equal real roots, and find the value of K

The discriminant △ = 0
That is, (2k-1) ^ 2-4 * k * k = 0,
It is reduced to - 4K + 1 = 0
The solution is k = 1 / 4

4x ＾ 2 + KX + 9 is a complete square, and K=
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