The area of a parallelogram is 48 square meters. The bottom of a triangle is equal to its height, which is twice as high. The area of this triangle is () square meters

The area of a parallelogram is 48 square meters. The bottom of a triangle is equal to its height, which is twice as high. The area of this triangle is () square meters


It's 48 square meters
Because the area of a triangle is equal to 1 / 2 × bottom × height
The area of a parallelogram is equal to the base x the height



The bottom of a triangle is 12 meters long. If the bottom is extended by 1 meter, the area will be increased by 4 square meters. How many square meters is the area of the original triangle?


12×(4×2÷1)÷2
=12×8÷2
=48 square meters



A triangle flag, it is a right triangle, the length of the three sides are 8 / 5 decimeter, 5 / 4 decimeter, 25 / 18 decimeter
What's the area of this flag in square decimeters?


The smaller two are right angles
So area = 1 / 2x8 / 5X25 / 18 = 9 / 40



A piece of cloth is 18.1 meters long and 1.6 meters wide. Use this cloth to cut two right triangle flags with right angle sides of 4 decimeters and 3 decimeters respectively. You can cut out at most______ Noodles


181÷3=60… 1, 16 △ 4 = 4, 60 × 4 × 2 = 480, so the answer is: 480



Use red paper to make right triangle flags. The right angle sides of the flags are 4 decimeters and 3 decimeters respectively. How many square decimeters of red paper is needed to make 15 such flags?
I hope it's in this format By /…… Except for


3 × 4 × 15 = 180 square decimeters



How many flags can you cut from a 60 decimeter long and 46 decimeter wide rectangular colored paper into a right triangle flag with a bottom and a height of 5 decimeters?


At most, it can cut such small flags = 2 × (60 △ 5) × [(46-1) △ 5)] = 216



A piece of red cloth is 30 meters long and 1.5 meters wide. How many right triangle flags can you make with it? How about the area of the flag


30*1.5=45㎡
45 * 100 = 4500 square decimeters
5 * 5 = 25 square decimeters
4500 / 25 = 180



The area of a triangle is 3 square meters, the height is unchanged, the bottom is expanded by 3 times, and the area of the triangle is ()


The area of the triangle is (9) square meters



B. C. D are all on the same line, △ ABC and △ CDE are equilateral triangles, ad and be intersect at point O, find the degree of ∠ BOD


120° ,∠BOD=180-∠OBD-∠ODB
=It is shown that ∠ oba + bad = 60 - ∠ OBD + ∠ bad, so ∠ bad + ∠ ODB + 120
In the same way, we can see that 120 = ∠ deo + ∠ ODB, so ∠ deo + ∠ ODB = ∠ bad ∠ ODB introduces ∠ deo = ∠ bad,
Therefore, the two triangles are congruent triangles, so ∠ BOD = 120 degree



As shown in the figure, given that points B, C and D are on the same straight line, △ ABC and △ CDE are equilateral triangles, be intersects AC at F, ad intersects CE at h, verification: FH ‖ BD


It is proved that: (1) both ∵ ABC and ∵ CDE are equilateral triangles, ∵ BC = AC, CE = CD, ∵ BCA = ∵ ECD = 60 °, ∵ BCA + ∵ ace = ∵ ECD + ∵ ace, that is,