There is a round skating rink in the park. Its perimeter is 502.4 meters. A 2-meter-wide path is paved around the rink. How many square meters is the area of the path?

Inner radius 502.4 △ 3.14 △ 2 = 80m
Outer radius 80 + 2 = 82m
Area 3.14 × (82 × 82-80 × 80)
=3.14×324
=1017.36 square meters

Pave a 2-meter-wide path around a 37.68-meter-long circular pool. How many square meters is the area of the path?

The radius of the small circle: 37.68 ÷ (2 × 3.14) = 37.68 ÷ 6.28 = 6 (m); the radius of the big circle: 6 + 2 = 8 (m); the area of the small road: 3.14 × (82-62) = 3.14 × (64-36) = 3.14 × 28 = 87.92 (M2); a: the area of the small road is 87.92 m2

There is a circular fish pond in Qingqing Park, with a perimeter of 18.84 meters. A 1-meter-wide path is paved around the pond to find the surface of the path

2πr=18.84
r=3
Then R2 = 3 + 1 = 4
The area of the path = π * R2 * R2 - π * r * r = 7, π = 21.98

In the park, there is a circular fish pond with a circumference of 37.68 meters, surrounded by a cobblestone path with a width of 1 meter. How many square meters is the area of this path?

The radius of fish pond is: 37.68 △ 3.14 △ 2 = 6m
The radius of the road is: 6 + 1 = 7m
So the area of the road is: 3.14 × 7-178; - 3.14 × 6-178; = 40.82 square meters

There is a circular fish pond in the youth park. The perimeter is 56.52 meters. There is a 2 meter wide cement road around the bath. How many meters is the area of this road
Quick answer, arithmetic!

The shape of cement pavement is concentric circle, and the area of concentric circle can be calculated,
R = 56.52 / 3.14 / 2 = 9
R = 9 + 2 = 11
S = 3.14 * 11 * 11-3.14 * 9 * 9 = 125.6m2

A rectangular flower garden is 20 meters long and 11 meters wide. A 2 meter wide circular ornamental road should be built around it. How many square meters is the area of the road?

(20 + 2 + 2) * (11 + 2 + 2) - 20 * 11 = 140 (M2)

A family area is going to build a circular flower garden with a perimeter of 28.26 meters. A 2-meter-wide circular road will be built around the flower garden. What is the area of the road and that of the flower garden
How much bigger?

28.26÷3.14=9
9÷2=4.5
3.14x4.5x4.5 = 63.585 M2
4.5+2=6.5
3.14x6.5x6.5-3.14x4.5x4.5 = 69.08m2
69.08-63.585 = 5.495 M2
The ring road covers an area of 5.495 square meters

On the edge of a circular flower garden with a circumference of 31.4 meters, build a circular stone road with a width of 1 meter. The area of this stone road is () square meters?

What is the radius of the flower bed
31.4 △ 3.14 △ 2 = 5 (m)
What is the outer radius of the path
5 + 1 = 6 (m)
What is the area of the stone road
6 × 6 × 3.14-5 × 5 × 3.14 = 34.54 (M2)

In order to beautify the campus environment, the school plans to pave a 2m wide circular path around the flower bed (as shown in the picture) with a perimeter of 37.68m. What is the area of the path? If 15 kg of cement is used per square meter, how many kg of cement is needed to pave this path?

Let R be the radius of the flower bed and R be the radius of the outer circle. According to the formula of the circumference of the circle, there are: 2 π r = 37.68, r = 6 (m), r = R + 2 = 6 + 2 = 8 (m). The area of this path is: S = π (r2-r2), = 3.14 × (82-62), = 87.92 (M2); 87.92 × 15 = 1318.8 (kg)

The school wants to lay a 2m wide circular stone path around a 62.8m circular flower bed. Please calculate the area of this path

The radius of flower bed: 62.8 △ 3.14 △ 2 = 10 (m) the area of path: 3.14 × (10 + 2) 2-3.14 × 102 = 3.14 × 144-3.14 × 100 = 3.14 × (144-100) = 3.14 × 44 = 138.16 (M2) a: the area of path is 138.15 m2

There is a round skating rink in the park. Its perimeter is 502.4 meters. A 2-meter-wide path is paved around the rink. How many square meters is the area of the path?