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What is the area formula of triangle and trapezoid?
The area formula of triangle (1) s △ = 1 / 2ah (a is the bottom of triangle, h is the height of the bottom) (2) s △ = 1 / 2acsinb = 1 / 2bcsina = 1 / 2absinc (three angles are ∠ a ∠ B ∠ C, opposite sides are a, B, C respectively, see trigonometric function) (3) s △ = √ [P (P-A) (P-B) (P-C)] [P = 1 / 2 (a + B + C)]
To solve the equation: a trapezoid has an area of 81 square meters and a height of 9 meters. The length of the upper bottom is half that of the lower bottom. There are more upper and lower bottom
Let the upper bottom be x meters and the lower bottom be 2x meters
81=9（X+2X)/2
X=6
Top and bottom = 6M
Bottom = 6 * 2 = 12m
The area of a trapezoid is 0.81 square meters, the height is 0.9 meters, the upper bottom is half of the lower bottom, and the sum is () M
0.81÷0.9÷4=0.225
A trapezoid has an area of 81 square centimeters and a height of 6 decimeters. Its bottom is four times that of its top. The bottom of this trapezoid is () cm?
Upper and bottom 81 × 2 ／ 60 ／ (1 + 4) = 0.54cm
Bottom 0.54 × 4 = 2.16 cm
What's the area of this trapezoid in square meters
A trapezoid, the product of height and bottom is 13 square meters and 16.2 square meters respectively
14.6
Area = (the sum of the top and bottom) times the height and then divided by 2
The height of a right angle trapezoid is 40 meters. If the bottom is reduced by 25 meters, the land will become a square. How many square meters is the original trapezoid area
The top and bottom of this right angled trapezoid is equal to the height of the trapezoid, which is 40 meters
Length of bottom = 40 + 25 = 65m
The area of the original trapezoid
=（40+65）*40/2
=105*20
=2100 square meters
The area of a trapezoidal land is 2400 square meters, 60 meters high, 27 meters long at the top and how many meters long at the bottom? (solution of a series of equations)
Let the bottom of trapezoid be x, (27 + x) × 60 △ 2 = 2400 & nbsp; & nbsp; (27 + x) × 60 = 4800, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 27 + x = 80, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 53, answer: let the bottom of trapezoid be 53m
The area of a trapezoid is 720 square meters, the upper bottom and height are 25 meters respectively. What is the lower bottom of this trapezoid?
I have listed the equation (25 + x) × 25 △ 2 = 720. If it's right, please write the solution. If it's wrong, help me to list the equation and solve it
Hello
The answer is as follows:
（25+x）×25÷2=720
25+x=720×2÷25
25+x=57.6
x=32.6
It is known that the area of trapezoid is 42 cm 2, the height is 6 cm, and its bottom is 1 cm less than 2 times of the top
According to the meaning of the question, we get y = 2x − 112 (x + y) × 6 = 42, and the solution is x = 5Y = 9. A: the upper bottom of the trapezoid is 5cm, and the lower bottom is 9cm
The bottom of a right angled trapezoid is 15cm. If the bottom is shortened by 3cm, the original trapezoid will become a square. The area of the original trapezoid is______ Square centimeter
(15-3 + 15) × (15-3) △ 2 = 27 × 12 △ 2 = 324 △ 2 = 162 (square centimeter). Answer: the original trapezoid area is 162 square centimeter. So the answer is: 162
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