There is a conical grain pile with a bottom radius of 3 m and a height of 2 M. if you stack these grains in a cylindrical grain bin with a bottom area of 6.3 square meters and a height of 3 m, can you put them down

There is a conical grain pile with a bottom radius of 3 m and a height of 2 M. if you stack these grains in a cylindrical grain bin with a bottom area of 6.3 square meters and a height of 3 m, can you put them down


The volume of cone is 1 / 3 × 3.14 × 3 & # 178; × 2 = 18.84 cubic meters
Volume of cylinder = 6.3 × 3 = 18.9 cubic meters
18.9>18.84
therefore
I can put it down



If the height of the cylinder is 2 / 3 of the height of the cone and the volume of the cone is 12 cubic decimeters, what is the volume of the cylinder?


Suppose the base area of the cone and the cylinder is s, and the height of the cone is h, then the height of the cylinder is 2 / 3H
Volume of cone v = 1 / 3 * s * H = 12 = > s * H = 36
Then the volume of cylinder v = s * (2 / 3H) = 2 / 3 * 36 = 24
So the volume of the cylinder is 24 cubic decimeters



The volume sum of a cone and a cylinder is 130 cubic centimeters. The height of a cone is twice as high as that of a cylinder. The bottom area of a cone is 2 / 3 of that of a cylinder
What is the volume of each? Please explain the juxtaposition in the simplest way


130 divided by (1 + 2 / 3) = 72 square cm (bottom area of cylinder) 72x3 2 / 3 = 48 cm
Let the height of the cylinder be xcm
72x x+48x1/3x 2x=130
72x+36x =130
x =4/5
72x4 / 5 = 90 cubic cm
130-90 = 40 cubic cm