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------It is known that the area of a right triangle is 10 √ 3cm square, and the length of one right side is 3 √ 2cm
Area = product of two right angles divided by 2
So the length of the other right angle side = 2 times the area divided by the right angle side = (2 * 10 √ 3) / (3 √ 2) = 10 √ 6 / 3
Given that the sum of the right sides of a right triangle is 10cm (1), when one of its right sides is 4.5cm, find the area 2, let the area be s, a right side
Given that the sum of the right sides of a right triangle is 10cm (1), when one of its right sides is 4.5cm, find the area. 2. Let the area be s, and one right side is xcm, find the functional relation of s with respect to X
Answer: (1) the length of the other right angle side is 10-4.5 = 5.5cm (the area of a right triangle can be divided by the product of two right angles and then divided by 2) the area s = &# 189; (4.5 * 5.5) = 12.375
（2）S=½*x*(10-x)
The three sides of a triangle are 4cm, 4cm and 5cm respectively. The maximum perimeter of a parallelogram formed by two such triangles is (),
The minimum is (). Write the formula
20 cm
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