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The length of the rectangle is (3a + 2b) meters, and the length is (a-b) meters more than the width
Given that the length of a rectangle is (2b-a) and the width is less than the length by B, then the circumference of the rectangle is ()
A. 3b-2aB. 3b+2aC. 6b-4aD. 6b+4a
∵ the length of the rectangle is (2b-a), the width is less than the length by B, ∵ the width of the rectangle is (2b-a) - B = B-A, ∵ the circumference of the rectangle is: 2 [(2b-a) + (B-A)] = 2 (3b-2a) = 6b-4a; therefore: C
If the circumference of a rectangle is 4A + 3b and the length is 2A + B-3, then the width is?
(4a+3b)/2-(2a+b-3)=1/2b+3
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