Given a ^ 2 + 3a-1 = 0, find the value of 3A ^ 3 + 10A ^ 2 + 2011
Because a ^ 2 + 3a-1 = 0
So: 3A ^ 3 + 10A ^ 2 + 2011
=3A³+9A²-3A+A²+3A-1+2012
=3A(A²+3A-1)+(A²+3A-1)+2012
=2012
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