Factorization: (do me a favor) (1)9（x+2）2-25（x+3）2 （2）a3-2a2b+ab2 （3）（ab+b）2-（a+b）2 （4）1-a2-4b2+4ab

Factorization: (do me a favor) (1)9（x+2）2-25（x+3）2 （2）a3-2a2b+ab2 （3）（ab+b）2-（a+b）2 （4）1-a2-4b2+4ab

Factorization factor 8a2-2

2(2a+1)(2a-1)

Junior high school mathematics problems can not be written out.. factorization
4X²+1/4-9y²-2X
（ab+1）²-（a+b）²
If the trilateral lengths a, B and C of △ ABC satisfy a & sup2; - AC = B & sup2; - BC, the shape of △ ABC can be judged
Can't show it? I change a way to see that square QQ does not show
4X2+1/4-9y2-2X
（ab+1）2-（a+b）2
Given the trilateral lengths a and C of △ ABC satisfying A2 AC = B2 BC, the shape of △ ABC can be judged
The next two are squares

1、4X²+1/4-9y²-2X = (4X²-2X+1/4) - 9y²
= (2x-1/2)² - 9y²
= (2x+3y-1/2)(2x-3y-1/2)
2、（ab+1）²-（a+b）² = （ab+1+a+b)(ab+1-a-b)
= [a(b+1)+(b+1)][a(b-1)-(b-1)
= (a+1)(b+1)(a-1)(b-1)
3. From a & sup2; - AC = B & sup2; - BC
a²-b² = ac-bc
(a+b)(a-b)=c(a-b)
Because a + B cannot be equal to C, A-B = 0 is necessary for the equation to hold
So a = B
That is, ABC is an isosceles triangle