1. When x takes what value, the value of the algebraic formula 2x-1 is smaller than that of the algebraic formula 5x + 6 by 1? 2. Solve the equation AX + 2 = 3x-3 (a is not equal to 3). Thank you, I want to be accurate

1. When x takes what value, the value of the algebraic formula 2x-1 is smaller than that of the algebraic formula 5x + 6 by 1? 2. Solve the equation AX + 2 = 3x-3 (a is not equal to 3). Thank you, I want to be accurate

2x-1+1=5x+6
5x-2x=-6
3x=-6
x=-2
ax+2=3x-3
3x-ax=2+3
(3-a)x=5
x=5/(3-a)

Equation - 4x (quadratic of x) + 3x = - 1,

By transforming 4x-3x-1 = 0 and then (x + 1) (4x-1) = 0, X is - 1 and a quarter

If AB is a constant and 2kx + A is equal to x-bk, no matter what the value of K is, its solution is always 1
Talk about the process

Is the equation: (2kx + a) / 3 = 2 + (x-bk) / 6
2（2kx+a）=12+x-bk,
4kx+2a=12+x-bk,
The solution is x = 1, so: 4K + 2A = 13 Bk,
（4+b）k=13-2a.
Because whatever the value of K is, the above equation holds
4+b=0,13-2a=0.
b=-4,a=13/2.

Given that C is a constant, the opposite number of a root of the equation x & sup2; - 3x + C = 0 is a root of the equation x & sup2; + 3x-c = 0
Given that C is a constant, the opposite number of a root of the equation x & # 178; - 3x + C = 0 is a root of the equation x & # 178; + 3x-c = 0. Find the root of the equation x & # 178; - 3x + C = 0 and the value of C

Let m be a root of the equation x & # 178; - 3x + C = 0 about X, - m be a root of the equation x & # 178; + 3x-c = 0
Then M & # 178; - 3M + C = 0
m²+3m-c=0
M = 0, C = 0
So the equation x & # 178; - 3x + C = 0 is X & # 178; - 3x = 0, X (x-3) = 0
X = 0 or x = 3
A: the root of X & # 178; - 3x + C = 0 is 0 or 3. The constant C is 0