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The bottom of a rectangular tin bucket is a cube with a side length of 25cm and a height of 40cm. How many square decimeters of tin is required to weld a pair of such buckets?
(25 * 25 + 25 * 40 + 25 * 40) * 2-25 * 25 * 2 = 4000 (square centimeter) = 40 (square decimeter)
The manufacturer of daily necessities makes a cylindrical uncovered iron bucket, 12 decimeters high and 10 decimeters in diameter at the bottom, making 10 such buckets
Do you need the area of iron sheet to make 10 such buckets?
Bottom area: 3.14 * (10 / 2) ^ 2 = 78.5 square decimeters
Side area: 3.14 * 10 * 12 = 376.8 square decimeters
Total area: 78.5 + 376.8 = 455.3 square decimeters
Total area of 10: 455.3 * 10 = 4553 square decimeters
To make a pair of uncovered rectangular tin buckets, the bottom is a square with a side length of 0.3 meters, and the bucket is 8 decimeters high. How much tin do you need at least
0.3 M = 3 decimeters
To make a cuboid tin bucket without cover, the area of the tin is
3 × 3 + 4 × (3 × 8) = 105 (square decimeter)
Then, to make a pair of uncovered rectangular iron bucket, the iron sheet should be at least 105 × 2 = 310 (square decimeter)
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