Make points P and O on the straight line OA and ob respectively to make MP + PQ + QN minimum, fast, very urgent

Make m the mirror point m 'of OA and n the mirror point n' of ob, connect M'n 'to OA, OB to R and s respectively, then RS is the result
The principle is that the line segment between two points is the shortest

As shown in the figure, point C is on line AB, and points m and N are the midpoint of AC and BC respectively. AC = 8cm, BC = 6cm, find the length of line Mn

Points m and N are the midpoint of AC and BC respectively, AC = 8cm, BC = 6cm, MC = AC △ 2 = 8 △ 2 = 4cm, NC = CB △ 2 = 6 △ 2 = 3cm. From the sum and difference of line segments, Mn = MC + NC = 4 + 3 = 7 (CM). Answer: the length of line segment Mn is 7cm

Line AB = 8cm, C is the point on line AB, AC = 3.2cm, M is the midpoint of AB, n is the midpoint of AC, find line Mn
Please write down the specific process.

Mn = 2.4, because n is the midpoint of AC, because AC is equal to 3.2, so NC is equal to 1.6. Because AB = 8, M is the midpoint of AB, so am is equal to 4, because AC is equal to 3.2, so cm is equal to 0.8, because Mn is equal to NC + cm is equal to 1.6 + 0.8, so 2.4-

If line AB = 16cm, C is a point on the extension line of AB, M is the midpoint of AC, and N is the midpoint of BC, then Mn =?

MN=CM-CN=AC/2-BC/2=(AB+BC)/2-BC/2=AB/2=8

If the line segment AB = 16cm, C is a point on the extension of AB, M is the midpoint of AC, and N is the midpoint of BC, what is Mn

Known: as shown in the figure, C is a point on the line AB, m ` n is the midpoint of the line AC ` BC respectively. AB = 11. Find Mn
A-----------M-----------C------N------B

AB=AC+CB
MN=MC+CN
AC=AM+MC CB=CN+NM
Because m, n is the midpoint of AC and BC
So am = MC, CN = nm
So AC = 2mc CB = 2cn
AB=2MC+2CN
AB=2MN
Mn = 1 / 2Ab = 5.5

From Xi'an railway station to Huashan railway station or Huashan north railway station is the nearest to Huashan?

Of course, Huashan railway station is much closer to Huashan

There is a section on both sides of a river that is parallel. There is a tree every 5 meters on this section of the river bank, and there is a telegraph pole every 50 meters on the other side of the river. When you look at the opposite bank 25 meters away from the bank, you can see that two adjacent telegraph poles on the opposite bank are just covered by two trees on this bank, and there are three trees between the two trees, so you can calculate the width of the river

As shown in the figure: AF = 25m, BC = 5 × 4 = 20m, de = 50m. Because BC ∥ De, BCDE = afag, that is 2050 = 2525 + FG, the solution is: FG = 37.5m. Through the test, FG = 37.5 is in line with the meaning. Therefore, the river width is 37.5m

A section of a river is parallel on both sides. On this Bank of the river, there is a big tree every 5 meters apart, and on the other bank, there is a telegraph pole every 50 meters apart
This bank is 24 meters away from the bank. When you look at the opposite bank, you can see that two adjacent poles on the opposite bank are just covered by two trees on this bank, and there are three trees between the two trees

Then the distance between the two trees is 5 * 4 = 20
Suppose the location of the person is a, the distance from the case is ab, and the distance from the opposite bank is AC = AB + BC
AB = 25, river width BC
So 20 / 50 = AB / AC = 25 / (25 + BC)
So BC = 75 / 2
25/(25+x) = 5*2/25
x=37.5

Standing 3M offshore, the man was 1.5m tall. Looking into the water, he saw the reflection of an electric pole on the other side of the river. The water surface was 0.5m lower than the river bank, and the river was 15m wide
Someone is 1.5m tall, standing 3M away from the river bank. When he looks into the water, he happens to see the reflection of a pole on the opposite bank of the river in the water. It is known that the water surface is 0.5m lower than the river bank, and the river is 15m wide. Calculate the length of the pole (specific process)

This question applies the similar triangle method to do:
Set: point O, head a, foot B, where people go to the river bank,
These three points form a triangle △ OAB;
The reflection of the top of the pole in the water C, the ground of the pole D, the point O from the man to the river bank,
These three points form a triangle △ OCD. These two triangles are similar triangles
According to the similar triangle, it is calculated as follows:
AB / OA = CD / OC
1.5m/3m = CD / 15m
CD=7.5M
Height of pole H = 7.5m-0.5m = 7M

Make points P and O on the straight line OA and ob respectively to make MP + PQ + QN minimum, fast, very urgent