We know that the two squares of the equation 2x + 3x-4 = 0 are x1, X2, and we do not understand the equation Find the value of the third power of X1 + the third power of x2

We know that the two squares of the equation 2x + 3x-4 = 0 are x1, X2, and we do not understand the equation Find the value of the third power of X1 + the third power of x2

According to the meaning of the title
x1+x2=-3/2
x1x2=-2
x³1+x³2
=(x1+x2)(x²1+x²2-x1x2)
=(x1+x2)[(x1+x2)²-3x1x2]
=-3/2×(9/4+6)
=-3/2×33/4
=-99/8

It is known that X1 X2 is two of the square of equation 2x + 3x-1 = 0. Solve the equation: 2x1 & # 178; + x1x2-3x2 & # 178;

x₁+x₂=-3/2、x₁x₂=-1/3、2x₁²+3x₁-1=02x₁²+x₁x₂-3x₂=1-3x₁+x₁x₂-3x₂=1-1/3-3(x₁+x₂)=2/3-3×(-3/2)=2...

We know that two of the equations 2x square + 3x-1 = 0 are x1, x2. We can solve the equation and find the value of (1) X1 square + x2 square
We know that two of the equations 2x square + 3x-1 = 0 are X1 and x2. We can solve the equation and find the values of the following formulas
(1) Square of X1 + square of x2
（2）x1-x2
（3）(1/x1)+(1/x2)
(4) Square of (x1 + x2) - x1-x2

Because X1 + x2 = - 3 / 2, X1 multiplied by x2 = - 1 / 2, this is a theorem. / is a division sign, the square of fraction line (1) X1 + x2 square = (x1 + x2) square -- 2x1x2 = 9 / 4 + 1 = 13 / 4 (2) because the square of (x1 -- x2) = X1 square + x2 square -- 2x1x2 = 13 / 4 + 1 = 17 / 4, X1 -- x2 may be positive or negative (3)