If the polynomial - 5x & sup3; - (2m-1) x & sup2; + (2-3n) X-1 about X does not contain quadratic term and linear term, the value of M, n is obtained As soon as possible, the better, before October 31 respondents add!

If the polynomial - 5x & sup3; - (2m-1) x & sup2; + (2-3n) X-1 about X does not contain quadratic term and linear term, the value of M, n is obtained As soon as possible, the better, before October 31 respondents add!

On the polynomial of x-5x & sup3; - (2m-1) x & sup2; + (2-3n) X-1 without quadratic and primary terms, then the coefficient before the quadratic and primary terms is 0, that is 2m-1 = 0, 2-3n = 0
So m = 1 / 2, n = 2 / 3

If the polynomial - 5x & sup3; - (2m-1) x & sup2; + (2-3n) X-1 about X does not contain quadratic term and primary term, then the polynomial of 2m-3n is obtained
If the square + (2-3n) X-1 of the cube - (2m-1) x of the polynomial-5 X of X does not contain quadratic and primary terms, the value of 2m-3n is obtained

-5-(2m-1)=0,-4-2m=0,m=-2
2-3n=0,n=2/3
2m-3n=-4-2=-6

How many times of multiplication and addition have been done for polynomial f (x) = X6 + 2x5 + 3x4 + 4x3 + 5x2 + 6x + 7 according to Qin Jiushao's algorithm?
When I figure it out, 6,6; and the answer is 5,6; who's wrong?

You are wrong. The final formula is x (x (x (x (x (x + 2) + 3) + 4) + 5) + 6) + 7. X + 2 is not multiplication, so there are 5 times of multiplication and 6 times of addition