When x =? The function y = x (3-2x), (0 less than x less than 3 / 2) has a maximum value, which is equal to?

When x =? The function y = x (3-2x), (0 less than x less than 3 / 2) has a maximum value, which is equal to?

y=x(3-2x)=3x-2x^2=-2(x^2-3/2x)=-2((x-3/4)^2-9/16)
So, when x = 3 / 4, y = 9 / 8 is the largest

The maximum value 0 of the basic inequality y = x (3-2x)

00
So 2Y = 2x (3-2x)

y=x(1-2x),(0
1L friends you calculate, should be 1 / 8! I use quadratic function, but the requirement is to solve inequality

Because 00
We can use the mean inequality
y=x(1-2x)=2x(1-2x)/2=

X + y equals 1, 2x + y equals 3, what is the solution

x + y = 1 ①
2x + y = 3 ②
② - 1
x = 2
Substituting x = 2 into (1) yields:
y = -1
In conclusion:
x = 2
y = -1

Y = [√ (2X-4) + √ (4-2x) - 1] / X-1 how much is 2x + 4Y equal to

Because to make two radicals hold, we need 2x = 4, so x = 2, so Next, I'll do it myself

If y = √ 2x-1 + √ 1-2x-1, what is the y-square of X

From the definition of inequality, we can get 1-2x > = 0 2x-1 > = 0, so x can only be equal to 0.5. When x = 0.5, y = - 10.5 to the negative power, so the Y side of X is equal to 2

8. It is known that y is inversely proportional to 2x + 1, and when x = 1, y = 2, then what is y equal to when x = 0?
9. If the function y = (m-1) x is an inverse proportional function, what is the value of M?

8. Y is inversely proportional to 2x + 1, i.e. y = K / (2x + 1)
When x = 1, y = 2, k = 6, so y = 6 / (2x + 1)
So when x = 0, y = 6
Square of 9. M power - 2?

When x = the function y = 2x (3-2x), (0

y=-4x²+6x
-b/2a=-6/2*(-4)=3/4=x
y= -4 * 9/16 + 6*3/4
= -9/ 4 + 18/4
= 9/4
When x = 3 / 4, the function y = 2x (3-2x), (0

What is 1-2 / 1-4 / 1-8 / 1-16 / 1-32
Simple algorithm, do not set

1-2 / 1-4 / 1-8 / 1-16 / 1-32 / 1
=1 - (1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32)
=31 / 1-32
=One out of 32

1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 +. + 1 / 256 is equal to?

Let s = 1 / 2 + 1 / 4 + +1/128+1/256
Then 2S = 1 + 1 / 2 + 1 / 4 + +1/128
therefore
S=2S-S
=1-1/256
=255/256