A+B=4 AB=3 2²+b²=?

A+B=4 AB=3 2²+b²=?

A+B=4 AB=3
A²+B²=(A+B)²-2AB=10

Given x-2y = 3, (X-2) (y + 1) = 2, find the value of XY, find the value of (X & # 178; - 2) (2Y + 1)

(X-2) (X-2) (X-2) (X-2) (y + 1) (X-2) (Y-2) (Y-2) (Y-2) (Y-2) (2) (2Y + 1) is the result of the (1) (x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\(3 ± √ 17) /

How to solve the equation 9 / A & # 178; + 24 / B & # 178; = 1 A & # 178; - C & # 178; = 4?
It's not a mistake. A & # 178; - B & # 178; = 4

Is it an ellipse?
Then a & # 178; - C & # 178; = B & # 178; = 4
So 9 / A and 178; + 6 = 1
a²

A & # 178; - B & # 178; = 4 9 / A & # 178; + 24 / B & # 178; = 1 this is a system of equations, find the value of a & # 178;, B & # 178,

Let x = A & # 178;, y = B & # 178; then the original equation is X-Y = 49 / x + 24 / y = 1, from 1 to x = y + 4, from 2 to 9y + 24x = XY, and from - 37x + 36 = 0, the solution is x1 = 1, X2 = 36, so X1 = 1, Y1 = 3x2 = 36, y2 = 32, so a & # 178; 1 = 1, B & # 178; 1 = 3A & # 178; 2 = 36, B & # 178; 1 = 32

If AB = 1, find the value of 1 + A & # 178; 1 / 1 + B & # 178; 1 / 1

ab=1
b=1/a
1 + A and 178; 1 / 1 + B and 178; 1 / 1
=1/（1+a²）+1/[1+(1/a)²]
=1/(1+a²)+1/(1+1/a²)
=1/(1+a²)+a²/(a²+1)
=(a²+1)/(a²+1)
=1

Divide 40 by 6
Don't say "Liuliu Dashun", otherwise it won't be reversed

This should be the most standard answer
(Lu, the capital of "6"; because 40 ／ 6 = 6.6666., so the idiom "40 / 6" is "one after another.")
Others like:
Six six infinite
bustling about

Half 40 divided by 6

One in two
40 divided by 6: endless

Divide forty by six and beat one

This should be the most standard answer
(Lu, the capital of "6"; because 40 ／ 6 = 6.666.., the idiom "40 / 6" means "one after another.")

Divide one by two to make one idiom

Divide into two

Divide 1 by 100 to make an idiom

1÷100=1/100
only one in a hundred is chosen