Calculate the multiplication and division of two integers (a-b + C-D) &# 178; - (a + B + C + D) &# 178;, calculated by square difference (2x-y + 1) & # 178; + (2x-y-1) & # 178; - 2 (2x-y + 1) (2x-y-1), calculated by complete square It's OK to write just one

Calculate the multiplication and division of two integers (a-b + C-D) &# 178; - (a + B + C + D) &# 178;, calculated by square difference (2x-y + 1) & # 178; + (2x-y-1) & # 178; - 2 (2x-y + 1) (2x-y-1), calculated by complete square It's OK to write just one

(a-b+c-d)²-(a+b+c+d)²=(a-b+c-d+a+b+c+d)(a-b+c-d-a-b-c-d)=(2a+2c)(-2b-2d)=-4(a+c)(b+d)(2x-y+1)²+(2x-y-1)²-2(2x-y+1)(2x-y-1),=(2x-y+1-2x+y+1)²=2²=4

Please give me some integral multiplication and division problems, the more the better, the best with answers, thank you very much

1、(3ab-2a)÷a2、（x^3-2x^y)÷(-x^2)3、-21a^2b^3÷7a^2b4、(6a^3b-9a^c)÷3a^25、(5ax^2+15x)÷5x6、(a+2b)(a-2b)7、(3a+b)^28、(1/2 a-1/3 b)^29、(x+5y)(x-7y)10、(2a+3b)(2a+3b)11、(x+5)(x-7)12、5x^3×8x^21...

How to calculate multiplication and division of integral in vertical form (urgent)
I want to calculate the vertical form of integral multiplication and division!

In multiplication and division of integers, integers in algebra are developed on the basis of the concept of numbers, so they retain many characteristics of numbers, and the contents and methods of research are also very similar. For example, the four arithmetic operations of integers can be compared with the four arithmetic operations of numbers in many aspects

Multiplication and division of integers, simplification of calculation,
1.(3a+7b-8)(3a+7b+8)
2.{(4x^3- 1/2y)^2+ 4y(2x^2- y/16)}÷(-2x)^2

1.(3a+7b-8)(3a+7b+8)
=[(3a+7b)-8][(3a+7b)+8]
=(3a+7b)^2-8^2
=9a^2+42ab+49b^2-64
2.{(4x^3- 1/2y)^2+ 4y(2x^2- y/16)}÷(-2x)^2
=(16x^6-4x^3y+1/4y^2+8x^2y-1/4y^2)÷(-2x)^2
=(16x^6-4x^3y+8x^2y)÷(-2x)^2
=16x^6÷(-2x)^2-4x^3y÷(-2x)^2+8x^2y÷(-2x)^2
=4x^4-xy+2y

Several questions about multiplication and division of integral
1. If (x + m) (x + 2) = x & sup2; - 5x + N, then M = -, n=——
If the product of (X & sup2; - Px + 3) (X-Q) does not contain X & sup2;, then——
A. P = q B = + - Q C. P = - Q D cannot be determined

（x+m)(x+2)=x²-5x+n
x²+2x+mx+2m=x²-5x+n
x²+(2+m)x+2m=x²-5x+n
Coefficient ratio (2 + m) = - 5
m=-7
2m=n
2(-7)=n
n=-14
D

On multiplication and division of mathematical integral
calculation:
1)(2m-n+3)(n+2m-3);
2)(x-2y+3)^2
3)200.1*199.9
4)9*11*101
5)498^2
6)3x(3x^2-4x+9)+(4x+5)(-4x-5);
7) Solution equation: 3 (x + 5) ^ 2-2 (x + 3) ^ 2 - (x + 9) (X-9) = 81
8) First simplify, then evaluate: (8x ^ 3 + 8x ^ 2 + 4x + 1) (8x ^ 3-8x ^ 2 + 4x-1), where x = 1 / 2

1.>> -n^2+6*n-5 #
2.>> x^2+2*x+1 #
3.>> (3999999)/(100) #
4.>> 9999 #
5.>> 248004 #
6.>> -39 #
7.>> 0 #
Do it yourself. Hahaha

It is known that the three sides of △ ABC are a, B and C respectively. (1) when B2 + 2Ab = C2 + 2Ac, try to judge the shape of △ ABC; (2) judge the sign of the value of formula A2-B2 + c2-2ac

(1) B2 + 2Ab = C2 + 2Ac can be changed to b2-c2 = 2ac-2ab, (B + C) (B-C) = 2A (C-B), because a, B, C are the three sides of △ ABC, so the relationship between B and C is either b > C or B < C. when b > C, B-C > 0, C-B < 0, which is not the problem; when B < C, B-C < 0, C-B > 0, which is not the problem. Then there is only one possibility, B = C. so this triangle is isosceles triangle. (2) a 2-b2 + c2-2ac = (A-C) 2-b2 = (A-C + b) (A-C-B) ∵ a, B and C are the lengths of △ ABC, and ∵ (A-C + b) > 0, (A-C-B) < 0, ∵ A2-B2 + c2-2ac < 0

(1) The n power of 2x is multiplied by the N-2 power of X, then the N-1 power of X is subtracted by the N-1 power of X, and then the N + 1 power of X is subtracted by the n-3 power of X
(2) The fourth power of (- 0.125) is multiplied by the fifth power of 4

1. 2n-2 power of = 2 * x-2n-2 power of x-2n-2 power of x = 02, = [(1 / 8) to the fourth power of X4 to the fifth power] = [(4 / 8) to the fourth power of X4] = 1 / 4

1. Find out the value of the following x (the complete process must be written)
(1) Known 4 ^ x = 2 ^ 3x-1
(2) It is known that 3 ^ x + 1.5 ^ x + 1 = 15 ^ 2x-3
(3) Known 2 ^ 2x + 3-2 ^ 2x + 1 = 192
2. It is known that 2 ^ a · 3 ^ B · 167 ^ C = 2004, where a, B and C are positive integers
(1) Finding the value of a, B, C
(2) Find the value of (a-b-c) ^ 2006
Note: for example, 2 ^ 2 is the power of 2, and "·" is a multiplier sign

1, (1) 4 ^ x = 2 ^ (2x) = 2 ^ (3x-1), so 2x = 3x-1, x = 1
(2) 3 ^ (x + 1) * 5 ^ (x + 1) = 15 ^ (x + 1) (because of the same number of times, it can be directly multiplied)
X + 1 = 2x-3, so x = 4
(3) 2 ^ (2x + 3) - 2 ^ (2x + 1) = 2 ^ (2x-1) (2 ^ 2-1) = 2 ^ (2x + 1) * 3 (first mention a 2 ^ (2x-1)). Thus 2 ^ (2x + 1) * 3 = 192, that is, 2 ^ (2x + 1) = 64 = 2 ^ 6
2x+1=6,x=2.5
2. (1) divide 2004 by 4 to get 501, then divide 167 to get 3, so a = 2, B = C = 1
(2) A-b-c = 2-1-1 = 0, so (a-b-c) ^ 2006 = 0

Help find integral multiplication and division method to calculate 10 questions ~ is the first semester of junior high school. The teacher asked to do. The best with answers

1) 66x + 17Y = 3967 25X + y = 1200 answer: x = 48 y = 47 (2) 18x + 23y = 2303 74x-y = 1998 answer: x = 27 y = 79 (3) 44x + 90Y = 7796 44x + y = 3476 answer: x = 79 y = 48 (4) 76x-66y = 4082 30x-y = 2940 answer: x = 98 y = 51 (5) 67x + 54y = 8546 71x-y = 56