Let a = (1, sin θ), B = (COS θ, 1) A.B = - 3 / 5, then sin 2 θ=

Let a = (1, sin θ), B = (COS θ, 1) A.B = - 3 / 5, then sin 2 θ=


a.b=cosθ+sinθ=-3/5
cos^2θ+sin^2θ+2sinθcosθ=9/25
sin2θ=9/25-1
sin2θ=-16/25