If the area of the triangle formed by the line y = 2x + B and the coordinate axis is 6, then the analytic expression of the function of the line is

y=2x+b,x=0,y=b;y=0,x=-b/2
|b*(-b/2)|*1/2=6
b^2/2=12
b=±2√6
Straight line y = 2x ± 2 √ 6

If the area of the triangle formed by the line y = - 2x + K and the two coordinate axes is 16, then what is the value of K

First, the intercept of the line on X and Y axes is obtained. When x = 0, y = k; when y = 0, x = K / 2. That is to say, the intercept of the line on X and Y axes is K / 2 and K respectively. The triangle area is 1 / 2 × K × K / 2 = (k ^ 2) / 4 = 16, and K = ± 8

If the area of the triangle formed by the line y = - 2x plus K and the two coordinate axes is 16, then the value of K is

y=-2x+k
Then y = 0, x = K / 2
x=0,y=k
So the area is | K / 2 * k | 2 = 16
k²=64
k=±8

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