It is known that the line y = KX + B passes through the point (2.5,0), and the area of the triangle surrounded by the coordinate axis is 6.25. The function analytical formula of the line is obtained
6.25*2=12.5
12.5/2.5=5
So this line intersects Y-axis (0,5)
Because 0 = 2.5k + B
5=0*k+b
So k = - 2
b=5
So y = - 2x + 5
Given that the images of the first-order function y = kx-4 and the positive scale function y = MX all pass through the point P (2, - 1), then the area of the triangle formed by the two straight lines and the X axis is?
Y = kx-4, the image passes through the point P (2, - 1),
-1=k*2-4,
K=3/2,
Y=3/2X-4,
The images of y = MX all pass through the point P (2, - 1),
-1=m*2,
m=-1/2,
y=-1/2x,
Y = 3 / 2X-4, solve the equation, x = 2, y = - 1
The straight line y = 3 / 2X-4, the intersection point with X axis is (8 / 3,0),
The area of the triangle formed by two straight lines and x-axis is?
1/2*8/3*1=4/3.
As shown in the figure, the known point B is on the image of the function y = 6 / x, and it is located in the first quadrant. Through point B, it is perpendicular to the x-axis and y-axis, and the perpendicular feet are points a and C,
Finding the area of rectangular oabc
If B (a, 6 / a) is set, OA = a, OB = 6 / A
Area of rectangular oabc = OA * ob = a * 6 / a = 6