It is known that the line y = KX + B passes through the point (2.5,0), and the area of the triangle surrounded by the coordinate axis is 6.25. The function analytical formula of the line is obtained

It is known that the line y = KX + B passes through the point (2.5,0), and the area of the triangle surrounded by the coordinate axis is 6.25. The function analytical formula of the line is obtained

6.25*2=12.5
12.5/2.5=5
So this line intersects Y-axis (0,5)
Because 0 = 2.5k + B
5=0*k+b
So k = - 2
b=5
So y = - 2x + 5

Given that the images of the first-order function y = kx-4 and the positive scale function y = MX all pass through the point P (2, - 1), then the area of the triangle formed by the two straight lines and the X axis is?

Y = kx-4, the image passes through the point P (2, - 1),
-1=k*2-4,
K=3/2,
Y=3/2X-4,
The images of y = MX all pass through the point P (2, - 1),
-1=m*2,
m=-1/2,
y=-1/2x,
Y = 3 / 2X-4, solve the equation, x = 2, y = - 1
The straight line y = 3 / 2X-4, the intersection point with X axis is (8 / 3,0),
The area of the triangle formed by two straight lines and x-axis is?
1/2*8/3*1=4/3.

As shown in the figure, the known point B is on the image of the function y = 6 / x, and it is located in the first quadrant. Through point B, it is perpendicular to the x-axis and y-axis, and the perpendicular feet are points a and C,
Finding the area of rectangular oabc

If B (a, 6 / a) is set, OA = a, OB = 6 / A
Area of rectangular oabc = OA * ob = a * 6 / a = 6