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2x+3y=15 解得自然数解為: x=0,y=0 x=3,y x=6,y= 補足プロセス: 2x=15-3y x=(15-3y)/2 x、yは自然数なので x≥0、15-3y≥0、15-3yは偶数です。 x≥0、y≤5、yは奇数 だから: x=0の場合、y=0 x=3の場合、y=3 x=6の場合、y=1
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