Let f (x) = x-x / 1-alnx, if f (x) has two extreme points x1x2, X1 belongs to the range of (0,1) x2 and (1,2) a

Let f (x) = x-x / 1-alnx, if f (x) has two extreme points x1x2, X1 belongs to the range of (0,1) x2 and (1,2) a

f(x)'=1/x^2(x^2-ax+1)=0
G (x) = x ^ 2-ax + 1 has two solutions in (0,2)
So g (0) * g (1)

Given the function y = x ^ 2 + 6x + 11, translate its image to vector a, get the image of function y = x ^ 2, and find the vector a

y=x^2+6x+11
=(x+3)^2+2
y=x^2=(x+3-3)^2+2-2
a=(-3,-2)

After the image of function y = 2x is translated according to vector a = (1,2), the corresponding analytical expression of the image is

The explanation of this vector is that it first moves to the right and then to the up, so y = 2 (x-1) + 2

The same function as y = x is y = x ^ 2 / x? Y = root x ^ 2 y = e ^ LNX y = log2 ^ 2 ^ x? Which is the same

The first X is not equal to 0, the second y ≥ 0, the third x > 0, only the fourth is the same