Let f (x) = 1 (x = 0) LG | x | (x ≠ 0) defined on R. if the equation F2 (x) + BF (x) + C = 0 has exactly three different real solutions x1, X2, X3, then X12 + X22 + X32=______ ．

Let f (x) = 1 (x = 0) LG | x | (x ≠ 0) defined on R. if the equation F2 (x) + BF (x) + C = 0 has exactly three different real solutions x1, X2, X3, then X12 + X22 + X32=______ ．

Let t = f (x), then the equation F2 (x) + BF (x) + C = 0 about X is equivalent to T2 + Bt + C = 0, and the image of F (x) is given as follows: from the image, we can see that when t = 1, the equation f (x) = 1 has three roots, when t ≠ 1, the equation f (x) = t has two different real roots, ｜ if the equation F2 (x) + BF (x) + C = 0 about X just

It is known that f (x) is an odd function defined on (- 1,1) and a decreasing function on (0,1). (1) find f (0)
2) If f (1-A) + F (1-2a) is less than 0, find the value range of A

(1)f(0)=0
(2)f(1-a)

Given that the function y = f (x) is a decreasing function defined from 0 to positive infinity and satisfies f (x.y) = f (x) + F (y), f (2-1) = 1, find the value of F (4-1) if f (2-x)
Given that the function y = f (x) is a decreasing function defined from 0 to positive infinity and satisfies f (x.y) = f (x) + F (y), f (2 / 1) = 1, find the value of F (4 / 1) if f (2-x)

f(1/4)=f[(1/2)*(1/2)]=f(1/2)+f(1/2)=1+1=2
Because y = f (x) is a decreasing function, so f (2-x) 1 / 4, which is the result of the previous question
So x0
Finally, take the intersection X