Given the line L1: (a + 2) x + (a + 3) Y-5 = 0 and the line l2:6x + (2a-1) Y-5 = 0, when the real number is what, the two lines are parallel to each other?

(a + 2) x + (a + 3) Y-5 = 0y = - (a + 2) x / (a + 3) + 5 / (a + 3) line L1 slope K1 = - (a + 2) / (a + 3) 6x + (2a-1) Y-5 = 0y = - 6X / (2a-1) + 5 / (2a-1) line L2 slope K2 = - 6 / (2a-1) because two lines are parallel, K1 = K2 - (a + 2) / (a + 3) = - 6 / (2a-1) (a + 2) (2a-1) = 6 (a + 3) 2A & # - 3A -

Given the line L1: (M + 2) x + (M + 3) Y-5 = 0 and the line l2:6x + (2m-1) = 5, find the value range or value of the real number m satisfying the following conditions: (1) L1 ‖ L2; (2) L1 ⊥ L2

(1) L1: (M + 2) x + (M + 3) Y-5 = 0, l2:6x + (2m-1) = 5, ∵ L1 ∥ L2, ∵ m + 26 = m + 32m − 1 ≠ 55, M = - 52, M = 4 (rounding), so m = - 52. (2) L1: (M + 2) x + (M + 3) Y-5 = 0, l2:6x + (2m-1) = 5, ∵ L1 ⊥ L2, ∵ 6 (M + 2) + (2m-1) (M + 3) = 0, M = - 1, or M = - 92

F (x) = x ^ 2-2mx + 2m-2 > 0, X belongs to the range of [0,1] for M

f(x)=x^2-2mx+2m-2=(x-m)^2-(m^2-2m+2)
Axis of symmetry x = m
M0, M > 1, no solution
0

If x ^ 2-2mx + 2m + 3 is a complete square, then M=

(2m/2)^=2m+3
m=3or-1

(x + Y-3) + (x-4) I = O for X and Y

x+y-3=0
x-4=0
x=4
y=-1

B（5,1/3）P（X＝2）＝?

This is a binomial distribution, and the answer is C 52 times one-third of the square and two-thirds of the cube is 80 / 243

If log3 (x) = - 1 / log4 (3), then x + x ^ 2 +. + x ^ n +=

∵log3(x)=-1/log4(3),
∴log3 x=log3 4
∴x=4
∴x+x^2+.+x^n=[x^(n+1)-x]/(x-1)=[4^(n+1)-4]/3

A person has RMB a for stock investment, and the annual dividend for purchasing a certain stock is 24%, (regardless of price factors and the stock company no longer issues new stocks, the annual dividend of the stock remains unchanged). He deposits the annual interest and dividend into the bank. If the annual interest rate of the bank is 6%, what is the total amount of RMB he owns after n years?
The answer is 4a (1.06 ^ n-1)

Consider the interest of the bank as a sequence, B (n), the sum of the first n items is s (n)
Then the first year interest is 24% a, let the total profit be C (n)
The annual dividend of the stock is always 24% a per year, recorded as C
b（n）=6％*c（n-1）
c（n）=s（n）+nc=s（n-1）+（n-1）c+b（n）+c
=c（n-1）+b（n）+c=1.06c（n-1）+c
=4a(1.06^n－1)
complete

We know that f (x) = (1 / 3) x ^ 3 - (1 / 2) ax ^ 2 + (A-1) x + 1
1. When a = 0, find the tangent equation of point (3,7)
2. If f (x) = 0 has two real roots, find the value range of A
Solving problems with the knowledge of derivative

F (x) = (1 / 3) x ^ 3 - (1 / 2) ax ^ 2 + (A-1) x + 1 f '(x) = x ^ 2-ax + a-11. When a = 0, f' (x) = x ^ 2-1 let the tangent point be (x0, Y0) a = 0f (x) = (1 / 3) x ^ 3-x + 1F '(x) = x ^ 2-1k = y' = x0 ^ 2-1k = (y0-7) / (x0-3) Y0 = 1 / 3 * x0 ^ 3-x0 + 1 ((1 / 3) x0 ^ 3-x0 + 1-7) / (x0-3) = 2x0 ^ 2-1

It is known that: M + 1 / 2 of M = 3, square of M + 1 / 2 of M =?

M + 1 / M = 3 square
m^2+2+1/m^2=9
Square of M + 1 / 2 of M = 7

Given the line L1: (a + 2) x + (a + 3) Y-5 = 0 and the line l2:6x + (2a-1) Y-5 = 0, when the real number is what, the two lines are parallel to each other?