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If XX + YY = 2, x + y = 1, then xy =?
(x + y) (x + y) = 1, expand, get xx + 2XY + YY = 1, substitute, get 2 + 2XY = 1, get xy = - 0.5
x. Find xx + YY with + y = 5, xy = 3
Because x + y = 5, so (x + y) square = x square + 2XY + y square = 25, so x square + y square = 25-3x2 = 19
X+y=6 xy=4 xx+yy=
xx+yy=(X+Y)(X+Y)-2XY=6*6-2*4=28
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