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Decomposition factor: 2XX + xy-yy-4x + 5y-6
The idea is that when the common factor is proposed, it should be MX (AX + by + C) + NY (AX + by + C) + ax + by + cm, N, a, B, C are all coefficients, so the only constant term C = - 6 (MC + a) x = - 4x is - 6m + a = - 4max x = 2XX is Ma = 2, M = 1, a = 2 (NC + b) y = 5Y is - 6N + B = 5nbyy = - 1yy
If x ^ 2-6y ^ 2 = - XY, x > 0, Y > 0 and X is not equal to y, then the value of (x + 3Y) / (X-Y) is_____ ?
x^2+xy-6y^2=0
(x+3y)(x-2y)=0
x=-3y or x=2y
Because x > 0, Y > 0, x = 2Y
The original formula is equal to 5
Given that x ^ 2-4xy + 3Y ^ 2 = 0, and XY is not equal to 0, find the value of X / y + Y / X
We know that x ^ 2-4xy + 3Y ^ 2 = 0 (1) And XY is not equal to 0, find the value of X / y + Y / X
x^2-4xy+3y^2=0
That is, (x-3y) (X-Y) = 0
So x = 3Y, or x = y
When x = 3Y, X / y + Y / x = 3 + 1 / 3 = 10 / 3
When x = y, X / y + Y / x = 2
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