What are the three elements of high school function

What are the three elements of high school function

The three elements are definition field, value field and corresponding relationship

I don't understand the three elements of a function in the book. I don't understand the corresponding relationship of a function. For example, the corresponding relationship between y = x and the square of y = (with the sign x) is the same. Where can I see that?

The three elements of function are: domain of definition, range of value and corresponding rule
As long as one of these three elements is different, then the function is different
The range of y = (√ x) & sup2; is nonnegative
The range of y = x is all real numbers
So they are different functions

What is the meaning of HL of the condition for judging the congruence of triangles
Please show me

The premise is a right triangle. If one right edge and one hypotenuse of the two triangles are equal, the two triangles are congruent. This condition of proving the congruence of triangles can only be used in right triangles dhttp://hiphotos.baidu.com/%CA%B7%D2%DD/pic/item/2df4ec4f31f9b522afc3abcb.jpg

Bivariate linear equation, 2x-y = - 4, 4x-5y = - 23

If you multiply 1 by 5 and subtract 2, you will get 1
10X-4X=-20-（-23）
The solution is x = 0.5
Substituting x = 0.5 into Formula 1
y=2x+4=2*0.5+4=5
So x = 0.5, y = 5

1. If the system of quadratic equations 2x + y = 3K with respect to x, y,
x+2y=-2
If the solution of K satisfies x + Y > 1, what is the range of K?
2. (1) solve the inequality
5（x-2）+8＜6（x-1）+7
If the minimum integer solution of the inequality in (1) is an equation
2X - AX = 3, find the value of A
3. The system of equations X-Y = 3 about X, y is known
2x+y=6a
The solution of a satisfies the inequality x + y < 3, and the range of real number a is obtained

1.k>5/3
2.a=7/2
3.a

If the solution of the binary linear equations ┌ 2x + y = 3K-1 └ x + 2Y = - 2 for X, y satisfies 0 ＜ x + y ≤ 1, the value range of K is obtained

The subject is very simple

Given that x = 2ky = − 3K is the solution of bivariate linear equation 2x-y = 14, then the value of K is ()
A. 2B. -2C. 3D. -3

By substituting x = 2ky = − 3K into the bivariate linear equation 2x-y = 14, 7K = 14 and K = 2 are obtained

Finding the range of a with solution of the equation sin ^ x + 2sinx + a = 0

sin²x+2sinx+a=0,
a=-sin²x-2sinx
=-(sinx+1)²+1,
When SiNx = - 1, a takes the maximum value of 1,
When SiNx = 1, the minimum value of a is - 3,
So sin ^ x + 2sinx + a = 0, the range of a with solution is [- 3,1]

Given that f (x) = 2A (COS ^ 2x / 2 + 1 / 2sinx) + B and X ∈ [0, π] (1) when a = 1, find the increasing interval of F (x), (2) when a < 0, the range of F (x) is [3,4], find a, B
It's cos ^ 2 (x / 2)

(1) F (x) = 2A (COS & # 178; X / 2 + 1 / 2sinx) + B = 2A [(cosx + 1) / 2 + 1 / 2sinx] + B = 2A (1 / 2cosx + 1 / 2 + 1 / 2sinx) + B = acosx + asinx + A + B = √ 2asin (x + π / 4) + A + B when a = 1, f (x) = √ 2Sin (x + π / 4) + 1 + B from 2K π - π / 2 ≤ x + π / 4

Find the sum of all solutions of the equation cos ^ 2x-sin ^ 2 = 1 / 2 in the interval [- 2 π, 2 π]

Cos ^ 2x-sin ^ 2x = cos (2x) = 1 / 2 solution has x = 2K π ± π / 3, K ∈ Z, so when k = - 2, X1 = - 11 π / 6, when k = - 1, X2 = - 7 π / 6, X3 = - 5 π / 6, when k = 0, X4 = - π / 6, X5 = π / 6, when k = 1, X6 = 5 π / 6, X7 = 7 π / 6, when k = 2, X8 = 11 π / 6, so the sum of all solutions of X on [- 2 π, 2 π] is: X1 + x2 + X3 + X4 +