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If the solutions of the equations 3x + y = 2k-4 and 2y-x = 2 about X and y satisfy x0, the value range of K is obtained We need to be more detailed
3x+y=2k-4 (2)
2y-x=2 (1)
(1)+3*(2)
3x+y+6y-3x=2k-4+6
7y=2k+2
y=(2k+2)/7
x=2y-2=2(k+2)/7-2
y>0,(2k+2)/7>0,2k+2>0,k>-1
x
Solve the equations, 3x + 5Y = 2, 4x-y = 1
3x+5y=2 (1)
4x-y=1 (2)
(2) The left and right sides of the formula multiply by 5 to get 20x-5y = 5 (3)
(1) Formula and (3) add to get 23x = 7, x = 7 / 23
Take x = 7 / 23 into any formula (1) or (2) to get y = 5 / 23
I don't know if it's right!
If (3x-2y) / (x + y) = 2 / 3, then 3x / 5Y=
∵(3x-2y)/(x+y)=2/3
∴3(3x-2y)=2(x+y)
9x-6y=2x+2y
9x-2x=2y+6y
7x=8y
x/y=8/7
∴3x/5y
=(3/5)×(x/y)
=(3/5)×(8/7)
=24/35
Please click the [select as satisfactory answer] button below
It is known that y = Y1 + Y2, where Y1 is inversely proportional to 3x and Y2 is positively proportional to - X. when x = 1, y = - 5 / 3; when x = 2, y = - 5 / 3=
It is known that y = Y1 + Y2, where Y1 is inversely proportional to 3x, Y2 is positively proportional to - x, and when x = 1, y = - 5 / 3; when x = 2, y = 3 / 2. (1) find the analytic expression of the function between Y and X (2) the value of y when x = - 1
Solution (1): let Y1 = m / (3x), y2 = - NX, then y = m / (3x) - NX substitute x = 1, y = - 5 / 3; X = 2, y = 3 / 2 into y = m / (3x) - NX to get the equation system of M, N: M / 3-N = - 5 / 3m / 6-2n = 3 / 2 solve the equation system, then M = - 29 / 3, n = - 14 / 9y and the function analytic expression of X is y = - 29 / (9x) + (14 / 9) x (2): when x = - 1, y
Given that Y1 = half of + 4, y2 = 3x-5, when x takes what value, Y1 is 3 times larger than Y2?
y1-y2
=x/2+4-2(3x-5)=3
11x/2=11
x=2
Let Y1 = (1 / 3) 3x-1, y2 = (2 / 3) - 2x, when determining why x refers, there are (1) Y1 = Y2 (2) Y1 > Y2 (3) Y1
y1=1/3*(3x-1)
y2=2/3-2x
When Y1 = Y2, x = 3 / 7
When Y1 = Y2, x > 3 / 7
When Y1 = Y2, X
Given y = Y1 + Y2, where Y1 is inversely proportional to 3x, Y2 is positively proportional to the square of X, and when x = 1, y = 6; when x = - 1, y = - 2. Find the relationship between Y and X, and the value of y when x = - 2
When the relation y = 4 / X 2x & # 178; X = - 2, y = 6, let Y1 * 3x = a, Y2 / X & # 178; = B substitute two known ones into a = 12, B = 2, Y1 = 4 / x, y2 = 2x & # 178; when the relation is - 2, substitute - 2 to get y value
When is Y1 greater than Y2
m> 2 or my2, B (2, Y2), so when m > 2, Y1 > Y2
Find the axis of symmetry of quadratic function as x = - B / 2A = - 3 / 2, the abscissa of the symmetric point of point B is - 5, so my2
It is known that Y1 = - 2x + 3, y2 = 3x-2
(1) When x takes what value, Y1 = Y2?
(2) When x takes what value, Y1 is less than Y2 by 5?
(1)-2x+3=3x-2
-5x=-5
x=1
(2)y2-y1=5
3x-2+2X-3=5
x=2
Let Y1 = 3x-2, y2 = 2x + 4, and Y1 = Y2, then the value of X is ()
A. 25B. 2C. 6D. 65
∵ Y1 = Y2 ∵ 3x-2 = 2x + 4 is reduced to x = 6, so C is selected
RELATED INFORMATIONS
- 1. When Y1 = 2X-4, y2 = - 3x + 5 and what is the value of X, Y1 > Y2
- 2. It is known that Y1 is equal to - x plus 3 and Y2 is equal to 3x minus 4. When x takes what value, Y1 is equal to Y2? When x goes where value, Y1 > Y2? When x takes what value, Y1
- 3. It is known that the equation of parabola is Y & # 178; = 2x, the straight line L passes through the fixed point (1,2), and the slope is K. when k is the value, the straight line L is the same as the parabola 1) There is one intersection; 2) there are two intersections; 3) there is no intersection
- 4. Y1 = 1 / 5x + 1, y2 = 2x + 1 / 4, when what is the value of X, Y1 and Y2 are opposite numbers?
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- 6. Solving binary linear equations x + 3Y = m, 5x-3y = m (M is a constant)
- 7. 5 / 12 - 1 / 3 = - 1 / 4 (one variable linear equation) the whole process
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