It is known that the equation of parabola is Y & # 178; = 2x, the straight line L passes through the fixed point (1,2), and the slope is K. when k is the value, the straight line L is the same as the parabola 1) There is one intersection; 2) there are two intersections; 3) there is no intersection

It is known that the equation of parabola is Y & # 178; = 2x, the straight line L passes through the fixed point (1,2), and the slope is K. when k is the value, the straight line L is the same as the parabola 1) There is one intersection; 2) there are two intersections; 3) there is no intersection

Write the equation of line L from the point oblique form: Y-2 = K (x-1), that is: y = K (x-1) + 2Y = K (x-1) + 2Y & # 178; = 2x series of equations, substitute x = y & # 178 / 2 into Formula 1, get: y = K (Y & # 178 / 2-1) + 2, sort out: KY & # 178; - 2y-2k + 4 = 01, when there is an intersection (1) k = 0, the equation has only one solution, that is the line and the parabola

There is only one common point between the parabola y = 2x ^ 2 and the straight line y = x + K with a slope of 1, so we can solve the linear equation

The discriminant is equal to zero
1+8k=0
So k = - 1 / 8
The linear equation is y = X-1 / 8

Given that Y1 = 5x-8, y2 = 12x + 6, when x takes what value, y1-1 / 3y2 = 2x?

y1=5x-8
y2=12x+6
y1-y2/3=2x
5x-8-4x-2=2x
-10=x
->When x = - 10
y1-y2/3=2x

Let Y1 = 1 / 5x + 1, y2 = 2x + 1 / 4, when x is what value, Y1 + Y2 is equal?

Question: let Y1 = 1 / 5x + 1, y2 = 2x + 1 / 4, when x is what value, Y1 and Y2 are equal?
∵y1=y2
Solving the equation, we get
1/5x+1=2x+1/4
Multiply both sides by 20 at the same time
4x+20=40x+5
36x=15
x=5/12

Given that Y1 = 2x + 3, y2 = 5x-1 / 2, if Y1 + 2Y2, then x=
Give 50 fortune

X=1/2

1. Let Y1 = 1 / 5x + 1, y2 = 2x + 1 / 4, when x is what value, y1y2 is opposite to each other

X = - 25 / 44 answer: teacher 086, Y1, Y2 are opposite numbers, so Y1 = - Y2, so 1 / 5x + 1 = - (2x + 1) / 4 multiply by 204x + 20 = - 10x-514x = - 25X = - 25 / 14 answer: teacher 077, Y1, Y2 are opposite numbers, then Y1 + y2 = 0

Find the intersection point of the line L &;: X-Y + 1 = 0 and L &;: 2x + Y-1 = 0
And the linear equation is parallel to the line L & # 8323;: y = 3x + 1

x-y+1=0
2x+y-1=0
At the same time, find out the intersection point (0,1)
The line is parallel to y = (3 / 4) x + 1,
So, the slope is 3 / 4
Therefore, the linear equation is y = (3 / 4) x + 1
Parallel to the known line, so the title is wrong

If the intersection coordinates of y = - x + A and y = x + B are (m, 8), then the value of a + B is ()
A. 32B. 24C. 16D. 8

∵ the intersection coordinates of the line y = - x + A and the line y = x + B are (m, 8), ∵ 8 = - M + A, 1, 8 = m + B, 2, 1 + 2, 16 = a + B, i.e. a + B = 16

If the intersection coordinates of y = - x + A and y = x + B are (m, 8), then the value of a + B is ()
A. 32B. 24C. 16D. 8

∵ the intersection coordinates of the line y = - x + A and the line y = x + B are (m, 8), ∵ 8 = - M + A, 1, 8 = m + B, 2, 1 + 2, 16 = a + B, i.e. a + B = 16

If the intersection coordinates of y = 3 + X and y = - x + B are (m, 8), then M --------, B -------

y=3+x
y=-x+b
The sum of the two formulas is: 2Y = 3 + B, y = (3 + b) / 2
The subtraction of the two formulas is: 0 = 2x + 3-B, x = (B-3) / 2
So two lines intersect at the point ((B-3) / 2, (3 + b) / 2)
So (3 + b) / 2 = 8, B = 15
m=(b-3)/2=12/2=6