Let X / (x ^ 2-mx + 1) = 1, where m is a constant. The detailed process of finding the value of x ^ 3 / (x ^ 6-m ^ 3x ^ 3 + 1)

Let X / (x ^ 2-mx + 1) = 1, where m is a constant. The detailed process of finding the value of x ^ 3 / (x ^ 6-m ^ 3x ^ 3 + 1)

Let X / (x ^ 2-mx + 1) = 1, where m is a constant. The detailed process of finding the value of x ^ 3 / (x ^ 6-m ^ 3x ^ 3 + 1)
X / (x ^ 2-mx + 1) = 1, that is, (x ^ 2-mx + 1) / x = 1, that is, x + 1 / x = 1 + M
Let the reciprocal of x ^ 3 / (x ^ 6-m ^ 3x ^ 3 + 1) be y
y = (x^6-m^3x^3+1)/x^3
= x^3 + 1/x^3 - m^3
= (x + 1/x)(x^2 + 1/x^2 - 1) - m^3
= (x + 1/x)[(x + 1/x)^2 - 3] - m^3
= (1+m)[(1+m)^2-3] - m^3
= 3m^2 - 2
So x ^ 3 / (x ^ 6-m ^ 3x ^ 3 + 1) = 1 / y = 1 / (3m ^ 2 - 2)

If the equation (m-1) x + 2 = 0 is a one variable linear equation about X, then the value range of M is ()
A. m≠0B. m≠1C. m=-1D. m=0

According to the characteristics of one variable linear equation, M-1 ≠ 0 and m ≠ 1 are obtained

The equation x3m-1 + 7m-5 = 0 of X is a linear equation of one variable. The value of M is? X3M, which means that the exponent of X is 3m-1

It's a linear equation of one variable
So the degree of X is 3m-1 = 1
3m=2
m=2/3
So the equation is x + 14 / 3-5 = 0
x=1/3

In the reaction 2x + y  2Z, it is known that 1.2gx reacts completely to form 2Gz. If the relative molecular mass of Y is 32, the relative molecular mass of Z is ()
A. 2B. 34C. 40D. 80

According to the law of mass conservation, the mass of Y is 2g-1.2g = 0.8g, and the mass of Y is 2g-1.2g = 0.8g, and the relative molecular mass of Z is a set of Z, and the relative molecular mass of Z is a set of Z, and the relative molecular mass of Z is a set of Z, and the relative molecular mass of Z is a set of a set of Z, and the relative molecular mass of Z is a set of a set of Z, and the relative molecular mass of Z of Z is a & nbsp & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp& nbsp; & nbsp; & nbsp; A = 40 so choose C

Solve the equations 2x + y + Z = 32, x + 2Y + Z = 19, x + y + 2Z = 21, find x, y, Z

4X + 4Y + 4Z = 72
X+Y+Z=18
So x = 14, y = 1, z = 3

Ask 2x + y = 2Z, the relative atomic mass of Y is known to be 32, X of 1.2g generates y of 2G, and find the relative atomic mass of Z?

The mass of Y is 2g-1.2g = 0.8g
2x + y = 2z
32 2m
0.8g 2g
32/0.8g=2m/2g
m=40
The relative molecular mass of Z is 40

3x-y = - 7, y + 2Z = 2, 2x-2z = - 5 for X, y, Z

3x-y=-7 …… one
y+2z=2…… two
2x-2z=-5…… three
Formula 1 + formula 2 + formula 3 gives x = - 2
Then substituting 1, we get y = 1
Substituting 3, we get z = 0.5

Equations 3x-y-z = 9, 2x + y-2z = 6, x + y + Z = 15

Write down the three formulas as Formula 1, formula 2 and formula 3 respectively
First, 3 * (formula 3) - (formula 1) = 4Y + 4Z = 36, then y + Z = 9 (formula 4)
Then 2 * (equation 3) - (equation 2) = y + 4Z = 24 (equation 5)
If z = 5 is solved by equation 4 and equation 5, then y = 4 is known by equation 4
From equation 3, we know that x = 6
So: x = 6, y = 4, z = 5

If 2x + y + 3Z = 10, 3x + 4Y + 2Z = 15, then x + y + Z=

2x+y+3z=10 (1)
3x+4y+2z=15 (2)
(1)+(2)
5x+5y+5z=25
So x + y + Z = 5

What is a cubic equation? (X -- 2Y = - 9, Y-Z = 3, 2Z + x = 47) is such a cubic equation?
The definition in the book says: each equation contains three unknowns and three formulas, but each equation has only two unknowns? Please answer. Do you have to have three formulas for the first-order equation of three variables? Please answer. What's the best way to solve the first-order equation of three variables? There are several solutions. If the answer is complete, 10 points will be added

The first problem: if it's a cubic equation, it must be an integral equation with three unknowns. But if it's a system of cubic equations, it needs to be an integral equation with three unknowns, and each equation is a quadratic equation. So you say (x-2y = - 9, Y-Z = 3, 2Z +...)