It is known that a two digit number is larger than the number on the single digit by 2, and the two digit number is larger than the number on the ten digit and the number on the single digit Given a two digit number, the number on the tenth digit is 2 times larger than the number on the single digit, and the two digit number is 4 times larger than the sum of the number on the tenth digit and the number on the single digit? The best solution is to offer a reward,

It is known that a two digit number is larger than the number on the single digit by 2, and the two digit number is larger than the number on the ten digit and the number on the single digit Given a two digit number, the number on the tenth digit is 2 times larger than the number on the single digit, and the two digit number is 4 times larger than the sum of the number on the tenth digit and the number on the single digit? The best solution is to offer a reward,

Let X be a ten digit number
6(x+x+2)+4=10(x+2)+x
12x+12+x=11x+20
2x=8
x=4
x+2=4+2=6
The two digit number is 64

If there is a two digit number, the number on the tenth digit is 6 times larger than the number on the single digit, and the two digit number is 2 times larger than the product of five times of the number on the single digit and the ten digit number

Let a bit be X
The tenth is x + 6
It's 10 (x + 6) + X
So 10 (x + 6) + x = 5x (x + 6) + 2
11x+60=5x2+30x+2
5x2+19x-58=0
(5x+29)(x-2)=0
x>0
x=2
x+6=8
A: the number is 82

If there is a two digit number, the number on the tenth digit is 5 times larger than the number on the single digit, and the two digit number is 5 times larger than the sum of the two digits, find the two digit number

Let X be the single digit, then x + 5 is the ten digit. From the meaning of the question, 10 (x + 5) + x = 8 [x + (x + 5)] + 5, the solution is: x = 1, then the two digit is 61