In AX = B, when a is not equal to 0, the equation has a unique solution (); when (), the equation has no solution; when (), the equation has innumerable solutions

In AX = B, when a is not equal to 0, the equation has a unique solution (); when (), the equation has no solution; when (), the equation has innumerable solutions

A = 0, B is not equal to 0, there is no solution;
A = 0, B = 0, there are innumerable solutions

The solution set of the equation AX + B = 0 is a finite set if and only if? I calculate that B is not equal to 0. If a = 0, X has no solution and is an empty set
Empty sets are also finite sets

If ~ a = 0, B doesn't matter how much ~ first of all, a is not equal to 0, otherwise the infinite set, because. A is zero, this equation is meaningless, take any real number OK ~, then B can be equal to 0 whenever it is on the molecule
To sum up, a is not equal to 0
P. S: if not, despise me ~ () / ~ bye

If a and B are opposite numbers and a ≠ 0, then the root of AX + B = 0 is

A:
a. B is opposite to each other, a ≠ 0
The sum of opposite numbers is 0: a + B = 0, B = - A
Substituting into the equation AX + B = 0, we can get:
ax-a=0
a(x-1)=0
Because: a ≠ 0
So: X-1 = 0
So: x = 1