Please compare the size of 2006 / 2007 and 2007 / 2008 in at least three different ways

Please compare the size of 2006 / 2007 and 2007 / 2008 in at least three different ways

Method 1: general division, change the denominator to the same, and then compare
Method 2: change the molecules of two fractions into the same, and then compare them
The above two methods are commonly used, but they are very complicated for this problem
Method 3: 2007 / 2006 = 1-2007 / 1, 2008 / 2007 = 1-2008 / 1
1 in 2007 is greater than 1 in 2008, so 1-2007 is less than 1-2008
So 2006 out of 2007 is less than 2007 out of 2008

The third power of (the second power of a + the second power of a + the second power of a)

The third power of (the second power of a + the second power of a + the second power of a)
=(3a^2)^3
=27a^6

-(- A to the 2nd power) to the 3rd power (- a) to the 3rd power △ to the 2nd power (- a)

-(- A to the 2nd power) to the 3rd power (- a) to the 3rd power △ to the 2nd power (- a)
=-The sixth power of a × the third power of a △ the second power of a
=-The seventh power of a

If (a + b) ^ 2-6 (a + b) + 9 = 1, then a + B = what

(a+b)^2-6(a+b)+9=1
(a+b-3)^2=1
(a+b-3)^2-1=0
(a+b-3+1)(a+b-3-1)=0
(a+b-2)(a+b-4)=0
A + B = 2 or a + B = 4

a=1,b=2.z=26
Puppies = 24911521
So 149114268151471091147 =? (prompt three words)

1-26 means 26 Pinyin letters
Dog = Xiaogou = 24 (x) 9 (I) 1 (a) 15 (0) 7 (g) 15 (0) 21 (U)
149114268151471091147 = 14 (n) 9 (I) 1 (a) 14 (n), 26 (z) 8 (H) 15 (o) 14 (n) 7 (g), 10 (J) 9 (I) 1 (a) 14 (n) 7 (g) = annual bonus

When a = - 1, B = - 2, - AB ^ 2=
Such as the title

-ab^2=－（－1）（－2）^2＝4

Define a ⁃ B = A-B ^ 2, then (1 ⁃ 2) ⁃ (- 3)=

1※2=1-2²=-3
(1※2)※(-3)=(-3)※(-3)=-3-（-3）²=-3-9=-12

It is known that a > 0, b > 0, and 1 / A + 2 / b = 1
(1) Find the minimum value of a + B; (2) if the line L and X axis, Y axis intersect with points a (a, 0), B (0, b), find the minimum area of △ OAB

Known: a > 0, b > 0 (a ≠ b), verification: 2 · √ (a ^ 2 + B ^ 2) > (√ 2) · (a + b)

Are you sure?

It is known that a > 0. B > 0. A + B = 1
Find 1 / A + 1 / B + 1 / AB greater than or equal to 8

Multiply both sides by AB, a + B + 1 ≥ 8ab
Because a + B = 1,1 + 1 ≥ 8ab -- > 1 ≥ 4AB
Because (a-b) square ≥ 0, so a square + b square - 2Ab ≥ 0
Two times + 4AB, a square + 2Ab + b square ≥ 4AB -- > (a + b) square ≥ 4AB
Because a > 0, b > 0 and a + B = 1, 1 ≥ 4AB, that is, the inequality is proved