If natural numbers a and B satisfy the following conditions: a-1b = 1182, a: B = 7:13, then a + B=______ ．

If natural numbers a and B satisfy the following conditions: a-1b = 1182, a: B = 7:13, then a + B=______ ．

a: The & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & & nbsp; & & nbsp; & & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; & nbsp; & nbsp; & nbsp & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp & nbsp; the & nbsp & nbsp & nbsp & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp; & nbsp; the & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; the & nbsp; the & nbsp; & nbsp; the & nbsp; the & nbsp; nbsp; nbsp; nbsp so the answer is: 240

If natural numbers a and B satisfy the following conditions: a-1b = 1182, a: B = 7:13, then a + B=______ ．

a: The & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & & nbsp; & & nbsp; & & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; nbsp; the & nbsp; & nbsp; & nbsp; & nbsp & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp & nbsp; the & nbsp & nbsp & nbsp & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp; & nbsp; the & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; & nbsp; the & nbsp; & nbsp; the & nbsp; the & nbsp; & nbsp; the & nbsp; the & nbsp; nbsp; nbsp; nbsp so the answer is: 240

Given the set a (- ∞, 0], B = {1, 3, a}, if a ∩ B ≠ 0, then the value range of real number a is______ ．

∫ 1 ∉ a, 3 ∉ a, and a ∩ B ≠ ∈, a ∈ a, and a = (- ∞, 0), the value range of real number a is (- ∞, 0], so the answer is: (- ∞, 0]

It is known that the equation ABS (x) = ax + 1 has a negative root and no positive root

|x| = ax + 1
x < 0,-x = ax + 1 x = -1/(a+1) a+1 > 0,a > -1
x> 0,x=ax+1,x=1/(1-a),1-a1.
The value range of a is a > 1

Given that the equation | x | = ax + 1 has a negative solution and no positive solution, the value range of a is obtained

The equation | x | = ax + 1 has a negative solution and no positive solution
∴ -x=ax+1
∴ (a-1)x=-1
When A-1 ≠ 0, that is, when a ≠ 1, x = - 1 / (A-1)
The equation has a negative solution and no positive solution
∴ -1/(a-1)＜0
A-1 > 0, i.e. a > 1
Therefore, the value range of a is all real numbers with a > 1

It is known that the equation | x | - AX-1 = 0 has a positive root and a negative root, then the value range of real number a is______ ．

The equation | x | - AX-1 = 0 has a positive and a negative root, which is transformed into the intersection of y = | x | and y = ax + 1. The abscissa is a positive and a negative one. The image of y = | x | and the image constant crossing point (0,1) of y = ax + 1 and y = ax + 1 are drawn. When the line from a to B satisfies the condition, so a ∈ (- 1,1) so the answer is (- 1,1)

Given that the equation x & sup2; - 1999x + a = 0 has two prime roots, find a

Let the root be m, n
(x-m)(x-n)=x²-(m+n)x+mn=x²-1999x+a=0
m+n=1999
a=mn
The sum of two prime numbers is 1999, which is odd
It's odd and even
My index is only 2
So 1999 = 2 + 1997
So a = 2 * 1997 = 3994

The sum of two prime numbers is 18, and the product is 65. What are the two prime numbers? Do not use the equation

Prime numbers below 18 are: 2, 3, 5, 7, 11, 13, 17
Where: 5 + 13 = 18, 7 + 11 = 18
Therefore, the product of 65 is only 5 and 13

x. If y is prime, how many solutions are there for the equation x + y = 1999

Because it can only be an odd prime plus an even prime, there are only two sets of solutions
x=2 ,y=1997
Or x = 1997, y = 2

Finding the solution set of inequality 2x-3 with absolute value greater than 5 (detailed process)
Use this formula to solve | a | - | B | ≤| a + B | ≤| a | + | B|
Because it's greater than 5, I don't know how to change them
If not, how to solve it?

|a|-|b|≤|a+b|≤|a|+|b|
Usually used to find the maximum, minimum or to prove inequality
Generally, we don't do this when solving, but we still need to analyze the absolute value
|2x-3|>5
That is, 2x-3 > 5 or 2x-34 or X