It is known that loga2 = m, loga3 = n. use M, n to represent loga18 and find the value of A2M + n,
loga18=loga 2+2loga 3=m+2n loga2=m,loga3=n ∴a^m=2 a^n=3 ∴a^(2m+n)=(a^m)×a^n=4×3=12
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