ABCD represents four different natural numbers and a × B × C × d = 2002, then a + B + C + D is the maximum and the minimum

ABCD represents four different natural numbers and a × B × C × d = 2002, then a + B + C + D is the maximum and the minimum

2002 factorization: 2 × 7 × 11 × 13 = 2002, that is, the minimum is 2 + 7 + 11 + 13 = 33
The maximum is: 1 + 2 + 7 + 143 = 153

Is ABCD four a natural number of 0? If a * b = C * D, then C / a = B / D () is right or wrong

Wrong
When a = D = 0, this formula is not true!

There are four natural numbers a, B, C and D. add each two of them to get six different sums
There are four natural numbers a, B, C and D. add each two of them to get six different sums, which are 59 / 66 / 53 / 55 / 42 / 49. What is the average of the four numbers

a+b=59
a+c=66
a+d=53
b+c=55
b+d=42
c+d=49
59+66+53+55+42+49=3a+3b+3c+3d=3(a+b+c+d)
59+66+53+55+42+49=