If the absolute value of X in X is 1, find X

If the absolute value of X in X is 1, find X


L x L / x = 1, then
lxl=x≠0
So x > 0



If the absolute value of X + 4 is added to the absolute value of Y-2 = 6
If the sum of the absolute value of X + 4 and the absolute value of X-2 = 6, find the range of X satisfying the condition


If the sum of the absolute value of X + 4 and the absolute value of X-2 = 6,
It is known that - 4 < x < 2



The solution set of absolute value x + 1 greater than - 1


The result is: (1) x + 1-2
Synthesis (1) (2) is: {- 2



What is the solution set of 1 / 2 x plus 1 whose absolute value is greater than or equal to 2,


(x / 2 + 1) > = 2 or (x / 2 + 1) = 1, so x > = 2
For the second, X



The solution of inequality about X: | X-1 | + | x-3 | > 4


According to the meaning of absolute value, | X-1 | + | x-3 | represents the sum of the distances from the corresponding points of X on the number axis to the corresponding points of 1 and 3, while the sum of the distances from the corresponding points of 0 and 4 on the number axis to the corresponding points of 1 and 3 is exactly equal to 4, so the solution set of | X-1 | + | x-3 | > 4 is {x | x < 0, or X > 4}



1.5 times x plus 18 is three times X


1.5X+18=3X 1.5X=18 X=12



18% = 6.5 of X


The answer is x = 4.68; 6.5 of X is the same as X: 6.5, and the product of the outer two terms is equal to the product of the inner two terms



Solve the equation x / 5 + (60-x) / 18 = 5.5


The equation is multiplied by 18 * 5 and becomes
18X+5(60-x)=5.5*18*5
18X+300-5X=495
13X=195
X=65



Solving equation 2 (x-2.6) = 8 (x-3) △ 2 = 7.5 8 (x-6.2) = 41.6


 



8 (x-6.2) = 41.6, there are two kinds of solutions, what's the difference?
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Method 1
X-6.2=41.6÷8
X-6.2=5.2
X=11.4
Method 2
8X-49.6=41.6
8X=91.2
X=11.4
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