Minus 300 times minus one eighth plus 0.125 times 54.5 plus minus five and one-half times minus 12.5% (- 300) * (minus one eighth) + 0.125 * 54.5 + (minus five and one half) * "(- 12.5%)

Minus 300 times minus one eighth plus 0.125 times 54.5 plus minus five and one-half times minus 12.5% (- 300) * (minus one eighth) + 0.125 * 54.5 + (minus five and one half) * "(- 12.5%)


(- 300) * (negative one eighth) + 0.125 * 54.5 + (negative five and one-half) * "(- 12.5%) = 300 x 1 / 8 + 1 / 8 x 54.5 + 11 / 2 x 1 / 8 = 1 / 8 x (300 + 54.5 + 5.5) = 1 / 8 x 360 = 45 donor, I see that you have a strange skeleton, elegant appearance and wisdom root, which is unique in all



If a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of M is 2, find the value of a-2013m + B-Cd


a. B is opposite to each other, a + B = 0
c. D is reciprocal, CD = 1
a-2013m+b-cd=a+b-cd-2013m=0-1-2013m
M is + and the result is - 4027
M is - and the result is 4025



If a, B are opposite to each other, C, D are reciprocal to each other, and the absolute value of M is 1, find the value of (a + BR) cd-2013m


If a, B are opposite to each other, C and D are reciprocal to each other, the absolute value of M is 1,
(a) cd-2013m
=0×1-2013m
=±2013;
I'm very glad to answer your questions. Skyhunter 002 will answer your questions
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It is known that - 1 / 3A ^ XB ^ 5 and 2A ^ 2B ^ x + y are the same kind of polynomials 3 / 4x ^ 3-1 / 3xy ^ 2 + 1/
The value of Y ^ 3


X = 2, y = 3
Then 3 / 4x ^ 3-1 / 3xy ^ 2 + 1 / y ^ 3 = 1 / 27



It is known that 1 / 3 A ^ (2x) y ^ (3Y) and - 7 / 9 A ^ (y + 1) B ^ (2x + 3) are of the same kind, so we can find the value of polynomial (x + y) ^ 2 - (X-Y) ^ 2


If a is of the same kind, then a and B have the same degree
So 2x = y + 1
3y=2x+3
y=2x-1
Substituting 3Y = 2x + 3
6x-3=2x+3
x=3/2
y=2x-1=2
So the original formula = (x + y + X-Y) (x + Y-X + y) = 4xy = 12



It is known that negative 2A ^ XB ^ X-Y and negative 1 / 6A ^ 5B ^ 2 are of the same kind. Find the value of 1 / 2x-2 (x-1 / 3Y ^ 2) + (negative 3 / 2x + 1 / 3Y ^ 2)


x=5
x-y=2
y=3
Just bring in the values of X and y



If the second power of (2x + 3) and the cube of Y + 2 are opposite, find x minus y
Is the arithmetic square root of Y + 2


Friends upstairs, cube root is not negative? Don't miss people, OK?
If you have a question, you can get it
(2x+3)²+√(y+2)=0
∵(2x+3)²≥0,√(y+2)≥0
∴2x+3=0,y+2=0
∴x=-3/2,y=-2
∴x-y=-3/2-(-2)=2-3/2=1/2



The square of (2x-y) multiplied by the cube of (y-2x) multiplied by the fourth power of (2x-y)


(2x-y)^2*(y-2x)^3*(2x-y)^4
=-(2x-y)^2*(2x-y)^3*(2x-y)^4
=-(2x-y)^(2+3+4)
=-(2x-y)^9



When a is greater than 0 and B is less than 0, | 6-5b | - | 3a-2b | - | 6b-1 | (simplification)
Simplify the following formula





Simplification: a > 0, b > 0