On the inequality e of X, the solution set of which X is greater than LNX is

On the inequality e of X, the solution set of which X is greater than LNX is


The answer is x > 0
∵ e ^ x > x, and x > LNX (when x > 0) ∵ e ^ x > LNX > 0
The definition domain of LNX is x > 0
So the answer is x > 0