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3.9 the solution set of inequality e ^ / LNX / > x ^ 2-2 is______ .
There are two cases
1) When LNX > 0, that is, x > 1, the inequality is equivalent to: e ^ LNX > x ^ 2-2, that is, x > x ^ 2-2
The solution of inequality (x-a) LNX + 1 > 0 about X
The transcendental equation itself is not easy to solve, and there is an unknown parameter a, which is definitely not a high school problem. If it's a undergraduate mathematics problem, it doesn't need to consider the inequality problem too much. So I guess it was written by the questioner himself
If the inequality x-m / LNX > root x is constant
Given the function f (x) = 2 times the root x-lnx-2. (1) find the monotone interval of F (x). (2) if the inequality x-m / LNX > root x is constant, find the set of values of real number M
Root X and LNX are monotone increasing functions. F (x) is monotone increasing function. The domain of definition of root x must be no less than 0, [0, infinite) monotone increasing
G (x) = x-m / lnx-radical x is an increasing function, but when x = 1, the function has a break point, and m makes it constant, which is impossible
RELATED INFORMATIONS
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- 2. Finding the derivative of (1 / LNX)
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