If a ^ 2-2ab-8b ^ 2 = 0 (AB is not equal to 0), then a / b=

If a ^ 2-2ab-8b ^ 2 = 0 (AB is not equal to 0), then a / b=

If a & # 178; - 2Ab + 8b & # 178; is equal to 0 (AB is not equal to 0), then a / b=

There's a new solution,
Because AB = / 0
Then B = / 0
Two sides of the equation divided by B ^ 2 become
（a/b）^2-2(a/b)+8=0
Let a / b square [(A / b) - 1] ^ 2 + 7 = 0 as a whole
So a / b = 1 + - √ 7I
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If a square-2ab-3b square = 0 (AB is not equal to 0), then the value of B of a + a of B is known as x square + XY + y = 14, y square + XY + x = 28, x + y?

This is the first time that we will be able to get 178; and then we will be able to carry out the following; (2a b-3b-3b-3b; (178; = 0 (a + b) (a-3b) (a-3b) = 0 (1) if a = -b: B / A + A / b = (-1) + (1) + (1) + (1) (2) if a = 3B: b-3b-3b-3b-3b; (178; = 0 (a + b) (a-3b) (a-3b) (a-3b) (a-3b) (a-3b) (a-3b-3b) (a-3b-3b) (a-3b-3b-3b-3b-3b-3b-3b-3b-178; + XY + y = 14, y \35\\\\35\\35\\\\\\\\\+ y = 42 (x + y

Given that B is not equal to the square of 0 a + the square of B + AB = 3AB, then a of B =?
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It is known that a + 3B = 0, then the quadratic power of a-3ab + 2B / the quadratic power of a + B is equal to 0

a+3b=0,
a=-3b
a²—3ab+2b²/a²+b²
=9b²+9b²+2b²/9b²+b²
=20b²/10b²
=2

Given that one part of m plus one part of M is equal to 2, how much is the square of m plus one part of M

1/m+m=2
Multiply both sides by m, 1 + M & sup2; = 2m
m²-2m+1=（m-1）²=0
So m = 1
So M & sup2; + 1 / M = 2

2m square - 5m-1 = 0, 1 / 2 of n square + 5 / 2 of n = 0, and M is not equal to N, find: 1 / 1 of M + 1 / N =?

1/n²+5/n-2=0 2n²-5n-1=0
M and N are two parts of the equation 2x & # 178; - 5x-1 = 0
From Veda's theorem
m+n=5/2 mn=-1/2
1/m +1/n=(m+n)/(mn)=(5/2)/(-1/2)=-5

The square of m plus m equals 1

m^2+m=1
m^2+m-1=0
m= (-1±√5) / 2

Let's know that m of n = 3 of 5, and find the value of (M + m of n) + (M-M of n) - (m square-n Square)

M / N = 3 / 5, then n / M = 5 / 3m / (M + n) + m / (m-n) - [n ^ 2 / (m ^ 2-N ^ 2)] = [M (m-n) + m (M + n) - n ^ 2] / (m ^ 2-N ^ 2) = (2m ^ 2-N ^ 2) / (m ^ 2-N ^ 2) = 1 + m ^ 2 / (m ^ 2-N ^ 2) = 1 + 1 / [1 - (n / M) ^ 2] = 1 + 1 / (1-25 / 9) = 1 + 9 / 16 = 25 / 16

Given that 1 / M-1 / N = m + 1 / N, then the square of (M / N-M / N) is?

1/m-1/n=(n-m)/mn=1/(m+n)
(n-m)(m+n)=mn
So n & # 178; - M & # 178; = Mn
So the original = [(M & # 178; - N & # 178;) / Mn] &# 178;
=(-mn/mn)²
=1