What is the sum of all even numbers within 100? As the title! Which is it! depressed
2+4+6+..+100=(2+100)*50/2=2550
What are even numbers within 100
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
What is the sum of even numbers within 100?
Such as the title
(2+100)*25=2550
How to do 1 * 3 / 1 3 * 5 / 1 5 * 7 / 1. (2n-1) * (2n 1) / 1 = 21 / 10
1,53'5688*563\1
Use VB to calculate s = 1 + 2 / 3 + 3 / 5 + 4 / 7 +. When the value of item I is less than 10 ^ - 5, it ends
Dim s as integerdim x as integerdim y as integers = 0x = 1y = 1while (x / Y > 10 ^ - 5) s = S + X / YX = x + 1y = y + 2wend
VB calculation 1-1 / 3! + 1 / 5! - 1 / 7! + +(- 1) ^ (n-1) / (2n-1)! Please fill in the blanks
Private Sub Command1_ Click()
Dim i As Integer,j As Integer
Dim n As Integer
Dim s As Double
j=1
s=1
n = Val(Text1.Text)
For i = 2 To n
j=__________ 'calculate 1 / (2 * i-1)!
s=_______________ 'l cumulative general term
Next i
text2.text=str(s)
j * (2 * i - 2) * (2 * i - 1)
s + (-1) ^ (n - 1) / j
Known arithmetic sequence {an}, 3,7,11,15, find
Is 4m + 19 (m ∈ n) a term in an?
Solution: since 4m + 19 = 4 (M + 5) - 1, why is 4 (M + 5) - 1
an = 4n-1
4m+19 = 4(m+5) -1
=>4m + 19 (m ∈ n) is a term in an
Known sequence 3, 7, 11 139 and 2, 9, 16 , 142, then the number of all their public items is ()
A. 4B. 5C. 6D. 7
The sequence 3, 7, 11 The general term formula of, 139 is an = 4n-1139, which is the 35th term of the sequence The general term formula of, 142 is BM = 7m-5142, which is the 21st term of the sequence The n-th term and the sequence 2, 9, 16 , 142, then 4N-1 = 7m-5, n = 7m − 44 = 7m4-1, M is a multiple of 4, M is less than 21, n is less than 35, so m can only be 4, 8, 12, 16, 20. At this time, the corresponding values of N are 6, 13, 20, 27, 34, so the number of public items is 5. So select B
Arithmetic sequence - 3, - 7, - 11, - 15 The general term formula of
An = (- 3) + (- 4) * (n-1) = 1-4n (n ≥ 1, n is a natural number)