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What does the physical formula s = 1 / 2at ^ 2 + VT + (12-t) × (V + at) mean What does this formula mean and what does it represent? Original title: A. B two cars drive in the same direction on the straight road. When B is 84m ahead of a, the speed of B car is 4m / s, and the acceleration of B car is 2m / s *. After a period of time, the acceleration of B car becomes 0. But a car has been moving at a constant speed of 20m / s, and after 12s, the two cars meet. What is the acceleration time of B car?
1 / 2at ^ 2 + VT is the displacement of car B when it accelerates uniformly, which is derived from the formula s = VOT + 1 / 2at ^ 2,
V + at is the final speed of vehicle B after time t,
(12-t) is the time for car B to move at a constant speed after T seconds of acceleration (because the total time is 12 seconds),
So (12-t) × (V + at) is the displacement of car B in uniform motion,
Therefore, s = 1 / 2at ^ 2 + VT + (12-t) × (V + at) is the total displacement of B vehicle's accelerating motion plus the displacement of uniform motion
What is the echo formula s = VT divided by 2 in physics
s: Distance between sound source and object v: sound propagation speed T: sound propagation time 2: there are going back, so divide by 2
What is the formula of displacement difference in physics compulsory one? What are the meanings of VT = V0 + at and S = at2 and what kind of problems are they applicable to?
Displacement difference s' = at ^ 2
Vt = V0 + at is suitable for the case that the initial speed is 0
S = at2, which is the displacement difference formula, is also used when the initial velocity is 0
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