Find the first n terms and Sn of sequence 1 / 2 ^ 2 + 4,1 / 4 ^ 2 + 8,1 / 6 ^ 2 + 12.1 / (2n) ^ 2 + 4N

1/{2^2+4]+ 1[/4^2+8]+1/[6^2+12]+...+1/[(2n)^2+4n]consider1/[(2n)^2+4n]=1/[4n(n+1)]=(1/4)[1/n -1/(n+1)]1/{2^2+4]+ 1[/4^2+8]+1/[6^2+12]+...+1/[(2n)^2+4n]=(1/4) [ (1/1-1/2)+(1/2-1/3)+...+(1/n-1/(n+1)]=(1...

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