Problems of Taylor formula in Higher Mathematics E (- x ^ 2 / 2) = 1-x ^ 2 / 2 + 1 / 2! (- x ^ 2 / 2) ^ 2 + O (x ^ 4), why is the infinitesimal of the peyano remainder o (x ^ 4) written like this? Instead of O ((- x ^ 2 / 2) ^ 2) = O (x ^ 4 / 4), I don't understand why?

Problems of Taylor formula in Higher Mathematics E (- x ^ 2 / 2) = 1-x ^ 2 / 2 + 1 / 2! (- x ^ 2 / 2) ^ 2 + O (x ^ 4), why is the infinitesimal of the peyano remainder o (x ^ 4) written like this? Instead of O ((- x ^ 2 / 2) ^ 2) = O (x ^ 4 / 4), I don't understand why?


Similarly, generally only write the coefficient of 1 (you can understand it as an order of magnitude, general mathematicians most want to know what order of magnitude a number is), O (x ^ 4) means x ^ 4 high-order infinitesimal, that is, LIM (O (x ^ 4) / (x ^ 4)) = 0. In other words, O (x ^ 4) is smaller than x ^ 4, which may be x ^ 5, x ^ 6



Find the first n terms and Sn of sequence (2 + 1 / 4), (4 + 1 / 16), (6 + 1 / 64), (2n + 1 / 4N)


=(2+4+.+2n)+(1/4+1/16+...+1/4^n)
=n(n+1)+[1/4^(n+1)-1/4]/(1/4-1)
=n(n+1)-(1/4^n-1)/3