Finding the sum of the first n terms of the sequence {1 / N (n + 3)} (eliminating the split terms)

The rest of them are (1 + 2) - 1 + (1 + 3) + (1 + 3)... (1 + 2) = (1 + 3) = (1 + 2) = (1 + 3) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) = (1 + 2) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) = (1 + 3) = (1 + 1) =

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