Given the square of a - 5A + 1 = 0 (a ≠ 0), find the square of a + the square of a / 1

Given the square of a - 5A + 1 = 0 (a ≠ 0), find the square of a + the square of a / 1

∵a≠0
The square of a-5a + 1 = 0 is divided by a at the same time
a-5+1/a=0
a+1/a=5
(a+1/a)²=25
a²+2+1/a²=25
a²+1/a²=23

Given the square of a-5a + 1 = 0, find the value of one-third of the square of a + a

No, it should be a ^ 2 + 1 / A ^ 2
From the known: A is not 0, both sides of the same divided by a: a + 1 / a = 5
a^2+1/a^2=(a+1/a)^2-2=5^2-2=23

Let me ask you a question: given the square of a - 5A + 1 = 0, find the square of a + one of the squares of a =?

Answer: because a square - 5A + 1 = 0, so (A-2) square - (a + 3) = 0, so a = 2 or - 3 Because a square - 5A + 1 = 0, so (A-2) square - (a + 3) = 0, so a = 2 or - 3 I'm sorry, the above is wrong. The real answer is 23